如何处理servlet？

Question

我试图创建一个简单的servlet应用程序，但是当我将它部署到我的Tomcat服务器（8.5）中时，localhost：8080给了我405方法不允许错误。 我不知道要处理此错误

我的pom.xml：

<?xml version="1.0" encoding="UTF-8"?> 
<project xmlns="http://maven.apache.org/POM/4.0.0" 
     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
     xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> 
    <modelVersion>4.0.0</modelVersion> 

    <groupId>com.devcolibri</groupId> 
    <artifactId>com.devcolibri.servlet</artifactId> 
    <version>1.0-SNAPSHOT</version> 
    <packaging>war</packaging> 

    <dependencies> 
     <dependency> 
      <groupId>javax.servlet</groupId> 
      <artifactId>javax.servlet-api</artifactId> 
      <version>3.1.0</version> 
     </dependency> 
    </dependencies> 

</project> 

我MainServlet.java

package com.devcolibri.servlet; 

    import javax.servlet.ServletException; 
    import javax.servlet.http.HttpServlet; 
    import javax.servlet.http.HttpServletRequest; 
    import javax.servlet.http.HttpServletResponse; 
    import java.io.IOException; 

    public class MainServlet extends HttpServlet { 


    @Override 
    protected void doGet(HttpServletRequest req, HttpServletResponse resp) 
      throws ServletException, IOException { 

     PrintWriter out = resp.getWriter(); 
     out.print("<h1>Hello Servlet</h1>"); 

    } 
} 

我的web.xml

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
     xmlns="http://java.sun.com/xml/ns/javaee" 
     xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" 
     version="3.0"> 

    <servlet> 
     <servlet-name>mainServlet</servlet-name> 
     <servlet-class>com.devcolibri.servlet.MainServlet</servlet-class> 
    </servlet> 

    <servlet-mapping> 
     <servlet-name>mainServlet</servlet-name> 
     <url-pattern>/</url-pattern> 
    </servlet-mapping> 

</web-app> 

Answer 1

我想我已经错过了很明显的：我怀疑你的战争文件不被部署在斜线。它可能被部署在您的工件ID下。要将其部署到主机的根目录，需要更多配置。尝试http://localhost:8080/com.devcolibri.servlet/

编辑：

或http://localhost:8080/com.devcolibri.servlet-1.0-SNAPSHOT/这应该是你的战争文件名。

Answer 2

它看起来像访问该servlet的方式不适用于doGet方法的受保护类型。请尝试doGet公开。

public void doGet(HttpServletRequest req, HttpServletResponse resp) 
     throws ServletException, IOException { 

    PrintWriter out = resp.getWriter(); 
    out.print("<h1>Hello Servlet</h1>"); 

} 

你可以参考这里了解保护和公众的更多信息：what is the difference between public service() method and protected service() method of httpservlet