列表分配索引超出范围错误

Question

我想创建一个简单的数组程序并打印出数组元素，但在我输入员工2的值后说：IndexError：list assignment index out of range。

#Create constant for the number of employees. 
SIZE = 3 

#Create an array to hol the number of hours worked by each employee. 
hours = [SIZE] 

#Get the hours worked by employee 1. 
hours[0] = int(input("Enter the hours worked by employee 1: ")) 

#Get the hours worked by employee 2. 
hours[1] = int(input("Enter the hours worked by employee 2: ")) 

#Get the hours worked by employee 3. 
hours[2] = int(input("Enter the hours worked by employee 3: ")) 

#Display the values entered. 
print("The hours you entered are:") 
print(hours[0]) 
print(hours[1]) 
print(hours[2]) 

Answer 1

值Python没有字面数组：它有名单。 hours = [SIZE]不会创建包含3个元素的列表：它会创建一个包含1个元素的列表。您应该使用append()将项目添加到列表中，而不是索引超过数组末尾。

正确的代码看起来像这样的元素添加到列表：

hours.append(int(input("Enter the hours worked by employee 1: "))) 
hours.append(int(input("Enter the hours worked by employee 2: "))) 
hours.append(int(input("Enter the hours worked by employee 3: "))) 

从评论，似乎你正在学习从伪教科书代码：这是美妙的。请记住，虽然某些常用于伪代码的惯例，或者有时类似于C语言的惯例在其他编程语言中可能会有所不同。例如，在C中，这声明了一个名为x的50个字符的数组。

char x[50]; 

在Python中，不能使用相同的语法。祝你好运。

Answer 2

您似乎对如何在Python中使用数组工作有错误的想法。本质上讲，当你键入

#Create constant for the number of employees. 
SIZE = 3 

#Create an array to hol the number of hours worked by each employee. 
hours = [SIZE] 

你在做什么是创建一个元素的数组的3

hours = [3]