MySQL定制组concat

我需要转换我的查询结果，因此多行具有相同的外键只是一行。我可以做到这一点与分组。问题是在我的一个列中，我想用不同的分组连接一些列。例如我的表包含somting这样的：MySQL定制组concat

shopId  Brand Category Color  QTY 
---------------------------------------------- 
15   Dell  NoteBook Red  5 
15   Dell  NoteBook Blue  1 
15   HP  NoteBook red  2 
15   HP  NetBook  red  3 
14   Sony  NoteBook yellow 1 
14   Acer  Tablet  red  10

品牌，类别和颜色都从他们的外键检索。我想现在这个结果像

ShopId  Dell Color    HP Color etc... 
----------------------------------------------------------- 
15   6  red:5, Blue:1  2  red:2  
14 ..............

我的查询

我通过shopId和使用金额和案例statment是一个很容易找到工作的每个品牌和类别的总数量划分它们。我的问题是我如何连接店铺，类别，品牌分组的颜色和数量（总分组由shopId不是商店，类别，品牌）？

我tabale是

 
CREATE TABLE `shopstorage` (
`color` int(11) NOT NULL, 
`category` int(11) NOT NULL, 
`brand` int(11) NOT NULL, 
`shop` int(11) NOT NULL, 
`date` date NOT NULL, 
`qty` tinyint(4) NOT NULL, 
PRIMARY KEY (`color`,`category`,`brand`,`shop`,`date`), 
KEY `clrEpClr` (`color`), 
KEY `clrEpCat` (`category`), 
KEY `clrEpshop` (`shop`), 
KEY `clrEpBrand` (`brand`), 
CONSTRAINT `SSBrand` FOREIGN KEY (`brand`) REFERENCES `brand` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION, 
CONSTRAINT `SSCat` FOREIGN KEY (`category`) REFERENCES `productcategory` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION, 
CONSTRAINT `SSClr` FOREIGN KEY (`color`) REFERENCES `color` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION, 
CONSTRAINT `SSShop` FOREIGN KEY (`shop`) REFERENCES `shop` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION 
) ENGINE=InnoDB DEFAULT CHARSET=utf8

和我的不完备查询

 
select 
    shop.name, shop.floor, shop.no, 
    sum(case when brand.name ='ASUS' and productcategory.name='NoteBook' then shopstorage.qty else 0 end) as ASUS, 
    sum(case when brand.name ='HP' and productcategory.name='NoteBook' then shopstorage.qty else 0 end) as HP, 
    sum(case when brand.name ='Sony' and productcategory.name='NoteBook' then shopstorage.qty else 0 end) as Sony, 
    sum(case when brand.name ='Dell' and productcategory.name='NoteBook' then shopstorage.qty else 0 end) as Dell, 
    sum(case when brand.name ='ASUS' and productcategory.name='NetBook' then shopstorage.qty else 0 end) as ASUS, 
    sum(case when brand.name ='HP' and productcategory.name='NetBook' then shopstorage.qty else 0 end) as HP, 
    sum(case when brand.name ='Sony' and productcategory.name='NetBook' then shopstorage.qty else 0 end) as Sony, 
    sum(case when brand.name ='Dell' and productcategory.name='NetBook' then shopstorage.qty else 0 end) as Dell, 
    sum(case when brand.name ='ASUS' and productcategory.name='Tablet' then shopstorage.qty else 0 end) as ASUS, 
    sum(case when brand.name ='HP' and productcategory.name='Tablet' then shopstorage.qty else 0 end) as HP, 
    sum(case when brand.name ='Sony' and productcategory.name='Tablet' then shopstorage.qty else 0 end) as Sony, 
    sum(case when brand.name ='Dell' and productcategory.name='Tablet' then shopstorage.qty else 0 end) as Dell 
from shopstorage 
    join brand on shopstorage.brand=brand.id 
    join color on shopstorage.color=color.id 
    join productcategory on shopstorage.category=productcategory.id 
    join shop on shop.id = shopstorage.shop 
group by shopstorage.shop

我正在寻找一种方式，每个总和后添加一列用于指定每种颜色的数量，例如，如果惠普是15它有7个红色和8个蓝色笔记本。我尝试了GROUP_Concat，但由于分组错误，它没有显示正确的结果。

来源

2012-08-13 Soheil

你想要一个“枢轴”。搜索那个术语 – Bohemian 2012-08-13 11:42:12

我已经在搜索那个。但坦克:) – Soheil 2012-08-13 12:05:43

向我们展示您的表结构（SHOW CREATE TABLE your_table'的结果）和您的查询到目前为止。 – Jocelyn 2012-08-13 13:39:13

我找出答案并希望与他人分享。我添加了下面的代码在我的查询中的每个总和后

,group_concat(case when brand.name='{$brand['name']}' and category={$category['id']} then concat(color.name,':',num) end) as {$brand['name']}C

{$品牌[“名称”]}和{$类别[“ID”]}是在我的PHP代码变量品牌和类别之间迭代我不知道为什么花了这么长时间找到这样一个简单的解决方案：P羞辱我：D

来源

2012-08-14 07:42:17 Soheil

MySQL定制组concat

回答

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