筛选ng选项

Question

我有2选择ng选项。我希望第二个选择重复选择name的values字段。

我发现的唯一解决方案是选择对象本身，而不仅仅是第一个选择中的名称字段（类似d as d.name for d in data） 但为了一致性我宁愿不要。

我可以使用过滤器或类似的东西来解决这个问题吗？

angular.module("App", []).controller("Ctrl", function($scope) { 
 
    $scope.data = [{ 
 
    name : "john", 
 
    values : ["Hello", "World"] 
 
    }, { 
 
    name : "peter", 
 
    values : ["Bonjour", "le", "monde"] 
 
    }]; 
 
});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script> 
 
<div ng-app="App" ng-controller="Ctrl"> 
 
<label>Name :</label> 
 
<select ng-model="name" ng-options="d.name as d.name for d in data"></select> 
 
<label>Value :</label> 
 
<select ng-model="value" ng-options="d as d for d in data"></select> 
 
</div>

Answer 1

喜欢这个？

angular.module("App", []).controller("Ctrl", function($scope) { 
 
    $scope.data = [{ 
 
    name : "john", 
 
    values : ["Hello", "World"] 
 
    }, { 
 
    name : "peter", 
 
    values : ["Bonjour", "le", "monde"] 
 
    }]; 
 
});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script> 
 
<div ng-app="App" ng-controller="Ctrl"> 
 
<label>Name :</label> 
 
<select ng-model="name" ng-options="d.name for d in data"></select> 
 
<label>Value : </label> 
 
<select ng-model="value" ng-options="d as d for d in name.values"></select> 
 
</div>

Answer 2

我不知道是否有更好的方法，但这是一种工作方式：现在

angular.module("App", []).controller("Ctrl", function($scope) { 
 
    $scope.data = [{ 
 
    name : "john", 
 
    values : ["Hello", "World"] 
 
    }, { 
 
    name : "peter", 
 
    values : ["Bonjour", "le", "monde"] 
 
    }]; 
 
});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script> 
 
<div ng-app="App" ng-controller="Ctrl"> 
 
<label>Name :</label> 
 
<select ng-model="name" ng-options="d.name as d.name for d in data"></select> 
 
<label>Value :</label> 
 
<select ng-model="value" ng-repeat="d in data" ng-if="name === d.name" ng-options="val for val in d.values"></select> 
 
</div>