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我用这个XMPP aSmack - How can I get the current user state (offline/online/away/etc.)?
代码与ejabbered和登录连接是安卓与Asmack - 如何检查用户在XMPP在android中的状态?
Class.forName("org.jivesoftware.smack.ReconnectionManager");
System.setProperty("smack.debugEnabled", "true");
ConnectionConfiguration connConfig = new ConnectionConfiguration(
XmppUtils.HOST, XmppUtils.PORT, XmppUtils.SERVICE);
connConfig.setSecurityMode(SecurityMode.disabled);
connConfig.setSendPresence(true);
XMPPConnection connection = new XMPPConnection(connConfig);
SASLAuthentication.supportSASLMechanism("PLAIN");
connConfig.setSASLAuthenticationEnabled(true);
connection.connect();
connection.login(Fblogin.fb_id, XmppUtils.PASSWORD);
Presence presence = new Presence(Presence.Type.available);
connection.sendPacket(presence);
setConnection(connection);
//Check the user onlcine or offline
Presence userFromServer=connection.getRoster().getPresence(TOCHATUSERNAME+"/Smack");
final int userState = XmppUtils.retrieveState(userFromServer.getMode(), userFromServer.isAvailable());
// Set the state
getActivity().runOnUiThread(new Runnable() {
@Override
public void run() {
if (userState==0) {
txt_membersgname.setText("offline");
} else if (userState==1) {
txt_membersgname.setText("online");
} else if (userState==2) {
txt_membersgname.setText("Busy");
}
}
});
public static int retrieveState(Mode userMode, boolean isOnline) {
/** 0 for offline, 1 for online, 2 for away,3 for busy*/
int userState = 0; // default return value
if (userMode == Mode.dnd) {
Log.e("busy", "busy");
userState = 3;
} else if (userMode == Mode.away || userMode == Mode.xa) {
userState =2;
} else if (isOnline) {
Log.e("online", "online");
userState = 1;
}
return userState;
}
我总是存在不可用,但如果我用下面的代码,它的工作原理正确
Presence userFromServer=connection.getRoster().getPresence(connection.getUser());
我在做什么错所以我如何获得其他用户存在?
存在userFromServer = connection.getRoster()getPresence(connection.getUser。 ());当我使用这个我看到的值connection.getUser()= 151083569134563 @ acqut/Smack – Raj 2014-10-31 09:48:51
我必须通过获取其他用户存在状态 – Raj 2014-10-31 09:49:25
请参阅。首先你必须得到这个特定用户可用的所有用户名和ID ..然后传递该ID来获得该用户的存在。 – 2014-10-31 09:52:01