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我想在django中进行“上下文”表单验证。考虑这种情况下:Django中的上下文表单验证
PLACE_TYPES = (
('RESTAURANT', 'Restaurant'),
('BARCLUB', 'Bar/Club'),
('SHOPPING', 'Shopping'),
)
RESTAURANT_FORMAT_CHOICES = (
('FAST_FOOD', 'Fast Food'),
('FAST_CASUAL', 'Fast Casual'),
('CASUAL', 'Casual'),
('CHEF_DRIVEN', 'Chef Driven'),
)
class Place(models.Model):
place_type = models.CharField(max_length=48, choices=PLACE_TYPES, blank=False, null=False)
name = models.CharField(max_length=256)
website_1 = models.URLField(max_length=512, blank=True)
hours = models.CharField(max_length=1024, blank=True)
geometry = models.PointField(srid=4326, blank=True, null=True)
#Restaurant Specific
restaurant_format = models.CharField(max_length=128, choices=RESTAURANT_FORMAT_CHOICES, blank=True, null=True)
所以在Django管理,用于放置相应的形式将有下拉菜单中包含“餐厅,酒吧,俱乐部”的选择,有一个名为“restaurant_format”另一个领域。
验证应确保restaurant_field不能为空,如果第一个下拉菜单设置为“餐厅”。
我想是这样的:
class PlaceAdminForm(forms.ModelForm):
def clean(self):
if self.cleaned_data['place_type'] == 'RESTAURANT':
if self.cleaned_data['place_type'] is None:
raise forms.ValidationError('For a restaurant you must choose a restaurant format')
,但得到这个错误:
异常类型:KeyError异常 异常值:
place_type
异常位置:/地点/管理。 py in clean,line 27