早上好将这些以不同的顺序,我有以下的(双语)XML片段:运用顺序编号作为子节点的属性值在一个父节点,然后在兄弟节点
<?xml version="1.0" encoding="UTF-8"?>
<tmx version="1.4">
<body>
<tu>
<prop type="x-Context">-2050338055591740051, -2050338055591740051</prop>
<prop type="x-Origin">TM</prop>
<prop type="x-ConfirmationLevel">Translated</prop>
<tuv>
<seg>
<ele>The text </ele>
<ele>
<ph x="0" type="QIAsymphony"/>
</ele>
<ele> goes </ele>
<ele>
<ph x="0" type="470"/>
</ele>
<ele> here </ele>
<ele>
<ph x="0" type="471"/>
</ele>
<ele>.</ele>
</seg>
</tuv>
<tuv>
<seg>
<ele>El texto </ele>
<ele>
<ph x="0" type="QIAsymphony"/>
</ele>
<ele> se mete </ele>
<ele>
<ph x="0" type="471"/>
</ele>
<ele> aquí </ele>
<ele>
<ph x="0" type="470"/>
</ele>
<ele>.</ele>
</seg>
</tuv>
</tu>
</body>
</tmx>
我首先想要将第一个tuv/seg节点中ph元素的x属性值从1到3(在这种情况下)编号。
但是,我得到的结果是这样的:
<tuv>
<seg>
<ele>The text </ele>
<ele>
<ph x="2" type="QIAsymphony"/>
</ele>
<ele> goes </ele>
<ele>
<ph x="4" type="470"/>
</ele>
<ele> here </ele>
<ele>
<ph x="6" type="471"/>
</ele>
<ele>.</ele>
</seg>
</tuv>
这是基于以下XSLT样式表:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="tmx">
<tmx><xsl:attribute name="version"><xsl:value-of select="./@version"/></xsl:attribute>
<xsl:apply-templates/>
</tmx>
</xsl:template>
<xsl:template match="body">
<body>
<xsl:apply-templates/>
</body>
</xsl:template>
<xsl:template match="tuv">
<tuv>
<xsl:apply-templates/>
</tuv>
</xsl:template>
<xsl:template match="prop">
<prop><xsl:attribute name="type"><xsl:value-of select="./@type"/></xsl:attribute>
<xsl:apply-templates/>
</prop>
</xsl:template>
<xsl:template match="tu">
<tu>
<xsl:apply-templates/>
</tu>
</xsl:template>
<xsl:template match="tuv[1]/seg">
<seg>
<xsl:for-each select="ele">
<xsl:choose>
<xsl:when test="child::ph">
<ele><ph><xsl:attribute name="x">
<xsl:number/>
</xsl:attribute>
<xsl:attribute name="type">
<xsl:value-of select="ph/@type"/>
</xsl:attribute>
</ph></ele>
</xsl:when>
</xsl:choose>
<xsl:choose>
<xsl:when test="child::text()">
<xsl:copy-of select="."/>
</xsl:when>
</xsl:choose>
</xsl:for-each>
</seg>
</xsl:template>
</xsl:stylesheet>
为了话,我需要以下结果:
<tuv>
<seg>
<ele>The text </ele>
<ele>
<ph x="1" type="QIAsymphony"/>
</ele>
<ele> goes </ele>
<ele>
<ph x="2" type="470"/>
</ele>
<ele> here </ele>
<ele>
<ph x="3" type="471"/>
</ele>
<ele>.</ele>
</seg>
</tuv>
最后,根据第一个tuv/seg节点中的类型属性值,我需要应用相应的荷兰国际集团的x值与x在第二TUV/SEG节点(在这种情况下将是不同的顺序)属性:
<tuv>
<seg>
<ele>El texto </ele>
<ele>
<ph x="1" type="QIAsymphony"/>
</ele>
<ele> se mete </ele>
<ele>
<ph x="3" type="471"/>
</ele>
<ele> aquí </ele>
<ele>
<ph x="2" type="470"/>
</ele>
<ele>.</ele>
</seg>
</tuv>
任何援助将不胜感激。
为什么你再次问同样的问题? http://stackoverflow.com/questions/25378898/numbering-placeholders-sequentally-in-a-node-based-on-sequence-in-which-they-ap – 2014-09-03 15:02:01