Lua - 涉及string.gsub的加密逻辑错误，加密输出不是输入

Question

我的程序似乎遇到了逻辑错误。我已经多次查看它，甚至编写了与此类似的另一个程序（似乎也有相同的错误）。我无法弄清楚什么是错的，但我认为它可能涉及我string.gsub的使用...

repeat 
local file = io.open("out.txt", "w") 
print("would you like to translate Cipher to English or English to Cipher?") 
print("enter 1 for translation to English. enter 2 for translation to Cipher") 
tchoice=io.read() 
if tchoice=="2" then 
print(" enter any text to translate it: ") 
rawtextin=io.read() 
text=string.lower(rawtextin) 
text1=string.gsub(text,"a","q") 
text2=string.gsub(text1,"b","e") 
text3=string.gsub(text2,"c","h") 
text4=string.gsub(text3,"d","c") 
text5=string.gsub(text4,"e","j") 
text6=string.gsub(text5,"f","m") 
text7=string.gsub(text6,"g","r") 
text8=string.gsub(text7,"h","g") 
text9=string.gsub(text8,"i","b") 
text10=string.gsub(text9,"j","a") 
text11=string.gsub(text10,"k","d") 
text12=string.gsub(text11,"l","y") 
text13=string.gsub(text12,"m","v") 
text14=string.gsub(text13,"n","z") 
text15=string.gsub(text14,"o","x") 
text16=string.gsub(text15,"p","k") 
text17=string.gsub(text16,"q","i") 
text18=string.gsub(text17,"r","l") 
text19=string.gsub(text18,"s","f") 
text20=string.gsub(text19,"t","s") 
text21=string.gsub(text20,"u","w") 
text22=string.gsub(text21,"v","t") 
text23=string.gsub(text22,"w","p") 
text24=string.gsub(text23,"x","u") 
text25=string.gsub(text24,"y","n") 
text26=string.gsub(text25,"z","o") 
text27=string.gsub(text26," ","@") 
print(text27) 
elseif tchoice=="1" then 
print("enter text!") 
rawtextin=io.read() 
text=string.lower(rawtextin) 
text1=string.gsub(text,"q","a") 
text2=string.gsub(text1,"e","b") 
text3=string.gsub(text2,"h","c") 
text4=string.gsub(text3,"c","d") 
text5=string.gsub(text4,"j","e") 
text6=string.gsub(text5,"m","f") 
text7=string.gsub(text6,"r","g") 
text8=string.gsub(text7,"g","h") 
text9=string.gsub(text8,"b","i") 
text10=string.gsub(text9,"a","j") 
text11=string.gsub(text10,"d","k") 
text12=string.gsub(text11,"y","l") 
text13=string.gsub(text12,"v","m") 
text14=string.gsub(text13,"z","n") 
text15=string.gsub(text14,"x","o") 
text16=string.gsub(text15,"k","p") 
text17=string.gsub(text16,"i","q") 
text18=string.gsub(text17,"l","r") 
text19=string.gsub(text18,"f","s") 
text20=string.gsub(text19,"s","t") 
text21=string.gsub(text20,"w","u") 
text22=string.gsub(text21,"t","v") 
text23=string.gsub(text22,"p","w") 
text24=string.gsub(text23,"u","x") 
text25=string.gsub(text24,"n","y") 
text26=string.gsub(text25,"o","z") 
text27=string.gsub(text26,"@"," ") 
print(text27) 
end 
print("writing to out.txt...") 
file:write(text27) 
file:close() 
print("done!") 
print("again? type y for yes or anything else for no.") 
again=io.read() 
until again~="y" 
x=io.read() 

在代码中没有错误 - 我在想什么？我意识到这不是最有效的方法，但我需要弄清楚在使用循环和表编写更高效的程序之前出了什么问题。

样品运行（只有显著数据附带）：

Answer 1

local decoded = 'abcdefghijklmnopqrstuvwxyz @' 
local encoded = 'qehcjmrgbadyvzxkilfswtpuno@ ' 

local enc, dec = {}, {} 
for i = 1, #decoded do 
    local e, d = encoded:sub(i,i), decoded:sub(i,i) 
    enc[d] = e 
    dec[e] = d 
end 

repeat 
    local file = io.open("out.txt", "w") 
    local text27, rawtextin 
    print("would you like to translate Cipher to English or English to Cipher?") 
    print("enter 1 for translation to English. enter 2 for translation to Cipher") 
    local tchoice = io.read() 
    if tchoice == "2" then 
     print(" enter any text to translate it: ") 
     rawtextin = io.read() 
     text27 = rawtextin:lower():gsub('.',enc) 
     print(text27) 
    elseif tchoice == "1" then 
     print("enter text!") 
     rawtextin = io.read() 
     text27 = rawtextin:lower():gsub('.',dec) 
     print(text27) 
    end 
    print("writing to out.txt...") 
    file:write(text27) 
    file:close() 
    print("done!") 
    print("again? type y for yes or anything else for no.") 
    local again = io.read() 
until again ~= "y"