您好,我有同样的问题,但很困惑,为什么它不起作用。致命错误:调用布尔型成员函数close()
Fatal error: Call to a member function close() on boolean in includes\register_check.php on line 45
这是$ stmt3-> close();
代码
} else {
if (strlen($_POST['username2']) < 2 || strlen($_POST['username2']) > 20) {
echo "<h3>Username must be between 2 and 20 characters!</h3>";
} else {
$stmt = yasDB_select("SELECT `id` FROM `user` WHERE `username` LIKE '$username'");
$stmt2 = yasDB_select("SELECT `id` FROM `user` WHERE `email` LIKE '$email'");
if ($stmt->num_rows == 0 && $stmt2->num_rows == 0) {
$stmt3 = yasDB_insert("INSERT INTO `user` (`username`, `password`, `repeatpassword`, `name`, `email`, `website`, `plays`, `points`, `date`) VALUES ('$username','$password','$repeatpassword','$name','$email','$website','$plays','$points', '$date')", false);
if ($stmt3) {
echo "<h3>Registered! You may now log in.</h3>";
} else {
$stmt3->close();
echo "<h3>Registration failed!</h3>";
}
} else {
$stmt->close();
echo "<h3>Sorry, username or email exists. Please try again.</h3>";
}
}
}
我怀疑这是因为'$ stmt3'为空。你从else调用它,if检查的值不是falsey。你可能想在'if'结果中找到那一行,而不是那个检查的结果。 – Carl
Sry我的意思是$ stmt3-> close();这给出了错误。 – funkstar33
虽然你正在修复的东西,你可能还想检查http://stackoverflow.com/questions/60174/how-can-i-prevent-sql-injection-in-php – apokryfos