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我正在创建数据分析仪表板。我将一个名为channel_param
的参数传递给MySQL数据源。基于mySQL IF-ELSE条件选择两个MySQL select查询
我想补充的,如果在这个查询语句首先检查channel_param参数值等于“ALL”
在“ALL”的情况下,下面的查询应执行:
SELECT
c.CountryCode, COUNT(f.`country_code_id`) AS view_count
FROM
fact_access_logs_views f
JOIN dim_country_code c ON f.`country_code_id` = c.`country_code_id`
JOIN dim_time_access d ON f.`access_time_id` = f.`access_time_id`
JOIN dim_channel chn ON f.`channel_id` = chn.`channel_id
在任何其他价值的情况下,该查询应执行:
SELECT
c.CountryCode, COUNT(f.`country_code_id`) AS view_count
FROM
fact_access_logs_views f
JOIN dim_country_code c ON f.`country_code_id` = c.`country_code_id`
JOIN dim_time_access d ON f.`access_time_id` = f.`access_time_id`
JOIN dim_channel chn ON f.`channel_id` = chn.`channel_id`
WHERE
chn.`shortname_chn` = ${channel_param}
我怎样才能做到这一点?
Mysql确实有IF()[refrence](http://stackoverflow.com/a/15265944/2586617) –