@ResponseStatus，客户端没有收到错误消息

Question

我有代码自定义异常：

@ResponseStatus(value = BAD_REQUEST, reason = "Login is busy") 
    public class LoginIsBusyException extends RuntimeException{ 
} 

而一个方法，可以把它：

@RequestMapping(method = POST) 
public void registration(@RequestBody UserRest user) throws 
LoginIsBusyException{ 
    userService.checkAlreadyExist(user.getLogin(), user.getMail()); 
    user.setActive(false); 
    UserRest userRest = userService.addUser(user); 
    Integer randomToken = randomTokenService.getRandomToken(userRest.getMail()); 
    mailService.sendMail(randomToken, userRest.getLogin(), userRest.getMail()); 
} 

的问题是，客户端只接收错误代码但未收到状态文本“登录很忙”，已尝试添加捕获此异常的方法

@ExceptionHandler(LoginIsBusyException.class) 
public void handleException(HttpServletResponse response) throws IOException 
{ 
    response.sendError(HttpServletResponse.SC_BAD_REQUEST, "Login is busy"); 
} 

但是，该消息某处丢失，客户得到这样的回应：

Answer 1

你已经错过了@ResponseBody您handleException方法并且还回报void与当前的代码，即，你是不是经过response体，如下图所示：

@ResponseBody 
@ExceptionHandler(LoginIsBusyException.class) 
public String handleException(HttpServletResponse response) throws IOException 
{ 
    response.sendError(HttpServletResponse.SC_BAD_REQUEST, "Login is busy"); 
} 

要不你用ResponseEntity同时生产标题和正文如下图所示

@ExceptionHandler(LoginIsBusyException.class) 
public ResponseEntity<String> 
       handleException(LoginIsBusyException exe) { 
    return ResponseEntity.status(HttpStatus.BAD_REQUEST).body("Login is busy"); 
}