获取表单数据并将其写入XML文件

Question

我正在尝试使用SimpleXML将表单数据（通过_POST）写入文档。这是我尝试过的，我似乎无法让它工作。

<?php 
$title = $_POST['title']; 
$link = $_POST['link']; 
$description = $_POST['description']; 

$rss = new SimpleXMLElement($xmlstr); 
$rss->loadfile("feed.xml"); 

$item = $rss->channel->addChild('item'); 
$item->addChild('title', $title); 
$item->addChild('link', $link); 
$item->addChild('description', $description); 

echo $rss->asXML(); 

header("Location: /success.html"); 

    exit; 
?> 

任何帮助或点在正确的方向将不胜感激。

Answer 1

，而不是使用的SimpleXMLElement您可以直接创建XML这样

$xml = '<?xml version="1.0" encoding="utf-8"?>'; 
$xml .= '<item>'; 
$xml .= '<title>'.$title.'</title>'; 
$xml .= '<link>'.$title.'</link>'; 
$xml .= '<description>'.$title.'</description>'; 
$xml .= '</item>'; 
$xml_file = "feed.xml"; 
file_put_contents($xml_file,$xml); 

可能，这将帮助你

Answer 2

您使用asXML（）函数错误。如果要将XML写入文件，则必须将文件名参数传递给它。检查SimpleXMLElement::asXML manual

所以你的代码行oututing XML应该从

echo $rss->asXML(); 

改为

$rss->asXML('myNewlyCreatedXML.xml'); 

Answer 3

有你的代码的几个问题

<?php 
$title = $_POST['title']; 
$link = $_POST['link']; 
$description = $_POST['description']; 

//$rss = new SimpleXMLElement($xmlstr); // need to have $xmlstr defined before you construct the simpleXML 
//$rss->loadfile("feed.xml"); 
//easier to just load the file when creating your XML object 
$rss = new SimpleXML("feed.xml",null,true) // url/path, options, is_url 
$item = $rss->channel->addChild('item'); 
$item->addChild('title', $title); 
$item->addChild('link', $link); 
$item->addChild('description', $description); 


//header("Location: /success.html"); 
//if you want to redirect you should put a timer on it and echo afterwards but by 
//this time if something went wrong there will be output already sent, 
//so you can't send more headers, i.e. the next line will cause an error 

header('refresh: 4; URL=/success.html'); 
echo $rss->asXML(); // you may want to output to a file, rather than the client 
// $rss->asXML('outfputfile.xml'); 
exit; 

？>