按列聚合高效分组

Question

SELECT date, id, sum(revenue) 
FROM table 
WHERE date between '2013-01-01' and '2013-01-08' 
GROUP BY date, id 
HAVING sum(revenue)>1000 

返回收入> 1000的行。

SELECT date, id, sum(revenue) 
FROM table 
WHERE date between '2013-01-01' and '2013-01-08' 
AND id IN (SELECT id FROM table where date between '2013-01-01' and '2013-01-08' GROUP BY id HAVING sum(revenue)>1000) 
GROUP BY date, id 

根据需要返回id在日期期间总收入大于1000的行。但是这个查询要慢得多。任何更快的方法来做到这一点？

Answer 1

确保您对date和id列的索引，并尝试这种变化：

select t.date, t.id, sum(t.revenue) 
from table t 
inner join (
    select id 
    from table 
    where date between '2013-01-01' and '2013-01-08' 
    group by id 
    having sum(revenue) > 1000 
) ts on t.id = ts.id 
where t.date between '2013-01-01' and '2013-01-08' 
group by t.date, t.id 

Answer 2

它不是MySQL的，它的Vertica的;）

克里斯，有什么投影和order by你CREATE TABLE使用???

你尝试使用database designer 看到http://my.vertica.com/docs/6.1.x/HTML/index.htm#14415.htm