我有一个字符串规则对的地图,我想创建一个“联合规则”(rule_t joint_rule;)以某种方式。如果我这样做是这样的:助推精神规则 - 规则连接
joint_rule = convert_logformat["%h"] >> convert_logformat["%t"];
比用parse_phrase联合统治字符串
std::string entry = "127.0.0.1 [16/Aug/2012:01:50:02 +0000]";
但如果我创建的联合统治这样匹配:
for (it = convert_logformat.begin(); it != convert_logformat.end(); it++)
{
joint_rule = joint_rule.copy() >> (*it).second.copy();
}
它确实不匹配相同的字符串。为什么?我怎么能实现类似于后者?
相关代码:
template <typename Iterator>
bool parse_logentry(Iterator first, Iterator last, std::vector<char>& ip, std::vector<char>& timestamp, std::vector<char>& req, unsigned int& status, unsigned int& transferred_bytes, std::vector<char>& referer, std::vector<char>& ua)
{
using boost::spirit::qi::char_;
using boost::spirit::qi::int_;
using boost::spirit::qi::uint_;
using boost::spirit::qi::phrase_parse;
using boost::spirit::ascii::space;
using boost::spirit::ascii::space_type;
using boost::phoenix::ref;
using boost::phoenix::push_back;
using boost::spirit::qi::_1;
using boost::spirit::qi::lexeme;
using boost::spirit::qi::rule;
typedef boost::spirit::qi::rule<Iterator, std::string(), space_type> rule_t;
rule_t ip_rule, timestamp_rule, user_rule, req_rule, ref_rule, ua_rule, bytes_rule, status_rule;
ip_rule %= lexeme[(+char_("0-9."))[ref(ip) = _1]];
timestamp_rule %= lexeme[('[' >> +(~char_(']')) >> ']')[ref(timestamp) = _1]];
user_rule %= lexeme[(+~char_(" "))];
req_rule %= lexeme[('"' >> +(~char_('"')) >> '"')[ref(req) = _1]];
ref_rule %= lexeme[('"' >> +(~char_('"')) >> '"')[ref(referer) = _1]];
ua_rule %= lexeme[('"' >> +(~char_('"')) >> '"')[ref(ua) = _1]];
bytes_rule %= uint_[ref(transferred_bytes) = _1];
status_rule %= uint_[ref(status) = _1];
std::map<std::string, rule_t> convert_logformat;
typename std::map<std::string, rule_t>::iterator it;
convert_logformat.insert(std::pair<std::string, rule_t>("%h", ip_rule));
convert_logformat.insert(std::pair<std::string, rule_t>("%t", timestamp_rule));
//convert_logformat.insert(std::pair<std::string, rule_t>("%r", req_rule));
//convert_logformat.insert(std::pair<std::string, rule_t>("%>s", status_rule));
//convert_logformat.insert(std::pair<std::string, rule_t>("%b", bytes_rule));
//convert_logformat.insert(std::pair<std::string, rule_t>("%u", user_rule));
//convert_logformat.insert(std::pair<std::string, rule_t>("%{User-agent}i", ua_rule));
//convert_logformat.insert(std::pair<std::string, rule_t>("%{Referer}i", ref_rule));
rule_t joint_rule;
//joint_rule = convert_logformat["%h"] >> convert_logformat["%t"];
for (it = convert_logformat.begin(); it != convert_logformat.end(); it++)
{
joint_rule = joint_rule.copy() >> (*it).second.copy();
std::cout << (*it).first << ": " << typeid((*it).second).name() << "\n";
}
std::cout << "convert_logformath: " << typeid(convert_logformat["%h"]).name() << "\n";
bool r = phrase_parse(first, last, joint_rule, space);
if (first != last)
return false;
return r;
}
什么是rule_t?你有这个SSCCE吗? http://meta.stackexchange.com/questions/22754/sscce-how-to-provide-examples-for-programming-questions/22762#22762 – sehe
typedef boost :: spirit :: qi :: rule rule_t; –
bayerb
http://pastebin.com/uT59AMQp – bayerb