MySQL报告 - 填写空日期

Question

我正在构建查询以返回每日销售数据。我目前的查询将返回类似于下面的表格：

---------------------------------- 
| DATE  | SKU  | TOTAL | 
---------------------------------- 
| 2014-11-01 | AV155_A | 209.00 | 
| 2014-11-02 | AV155_B | 627.00 | 
| 2014-11-04 | AV155_C | 279.00 | 
| 2014-11-05 | AV155 | 279.00 | 
| 2014-11-08 | AV1556_A | 209.00 | 
| 2014-11-09 | AV1556_B | 627.00 | 
| 2014-11-10 | AV1556_C | 279.00 | 
| 2014-11-12 | AV1556 | 279.00 | 

我想是一个成绩表显示每一天，即使有该日期没有数据点。事情是这样的：

---------------------------------- 
| DATE  | SKU  | TOTAL | 
---------------------------------- 
| 2014-11-01 | AV155_A | 209.00 | 
| 2014-11-02 | AV155_B | 627.00 | 
| 2014-11-03 |   |  0 | 
| 2014-11-04 | AV155_C | 279.00 | 
| 2014-11-05 | AV155 | 279.00 | 
| 2014-11-06 |   |  0 | 
| 2014-11-07 |   |  0 | 
| 2014-11-08 | AV1556_A | 209.00 | 
| 2014-11-09 | AV1556_B | 627.00 | 
| 2014-11-10 | AV1556_C | 279.00 | 
| 2014-11-11 |   |  0 | 
| 2014-11-12 | AV1556 | 279.00 | 

查询我目前有看起来像这样：

select 
    DATE_FORMAT(created_on, '%m-%d-%Y') as date, 
    sku, 
    SUM(price) as total 
FROM order_items 
WHERE created_on between FROM_UNIXTIME(1415577600) AND NOW() 
GROUP BY MONTH(created_on), DAY(v.created_on), order_item_sku; 

Answer 1

您需要使用外连接。最简单的方法是，如果你有一个日历表，但你可以做一个在飞行：

select c.thedate, oi.sku, sum(price) as total 
from (select date('2014-11-01') as thedate union all 
      date('2014-11-02') as thedate union all 
      date('2014-11-03') as thedate union all 
      date('2014-11-04') as thedate union all 
      date('2014-11-05') as thedate union all 
      date('2014-11-06') as thedate union all 
      date('2014-11-07') as thedate union all 
      date('2014-11-08') as thedate union all 
      date('2014-11-09') as thedate union all 
      date('2014-11-10') as thedate union all 
      date('2014-11-11') as thedate union all 
      date('2014-11-12') as thedate 
    ) c left join 
     order_items oi 
     on c.thedate = date(oi.created_on) 
where oi.created_on between FROM_UNIXTIME(1415577600) AND NOW() 
group by ci.thedate, oi.sku 

Answer 2

下面是解决了日期的灵活列表需要一个答案。您需要找出一种方法来获取包含适当范围内所有日期的虚拟表格，然后将它们加入摘要。这是一个查询，将获得该范围内的日期。

SELECT mintime + INTERVAL seq.seq DAY AS reportdate 
    FROM (
     SELECT MIN(DATE(created_on)) AS mintime, 
       MAX(DATE(created_on)) AS maxtime 
      FROM order_items 
     WHERE created_on >= starting_time 
      AND created_on <= NOW() 
     ) AS order_items 
    JOIN seq_0_to_999 AS seq 
        ON seq.seq < TIMESTAMPDIFF(DAY,mintime,maxtime) 

这是怎么回事？三件事。

1. 我们有一个子查询，它决定我们关心报告的第一天和最后一天（最小和最大created_on）。

2. 我们将时间范围应用于该查询。我喜欢避免使用BETWEEN作为时间戳范围，因为它经常在错误的一秒错误中得到错误的结束时间。

3. 我们有一个名为seq_0_to_999的表。它包含一千个基数的序列：从零开始的整数。更多关于这一点。

然后，您可以将其作为子查询加入到您的聚合查询中，以获取所列范围中的所有日期，如此。

select DATE_FORMAT(d.reportdate, '%m-%d-%Y') as date, 
     sku, 
     SUM(price) as total 
    FROM (
      SELECT mintime + INTERVAL seq.seq DAY AS reportdate 
      FROM (
        SELECT MIN(DATE(created_on)) AS mintime, 
         MAX(DATE(created_on)) AS maxtime 
        FROM order_items 
        WHERE created_on >= starting_time 
        AND created_on <= NOW() 
       ) AS order_items 
      JOIN seq_0_to_999 AS seq 
           ON seq.seq < TIMESTAMPDIFF(DAY,mintime,maxtime) 
     ) AS d 
    LEFT JOIN order_items ON d.reportdate = DATE(order_items.created_on)  
    WHERE created_on >= starting_time 
    AND created_on <= NOW() 
    GROUP BY d.reportdate, sku 
    ORDER BY d.reportdate, sku 

它看起来像一个查询大讨厌的毛球。但是，如果您将其视为由各种查询层组成的三明治，则确实不那么复杂。

它使用LEFT JOIN，因此它确保即使您的order_items表中没有相应的数据，该范围内的所有日期都会保留。

最后，这个seq_0_to_999表怎么办？我们从哪里获得从零开始的整数？答案是这样的：我们必须安排这样做;这些数字不是内置在MySQL中的。 （它们被构建到名为MariaDB的MySQL分支中。）在其0-9创建一个整数短表，就像这样：

DROP TABLE IF EXISTS seq_0_to_9; 
CREATE TABLE seq_0_to_9 AS 
    SELECT 0 AS seq UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 
    UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9; 

然后创建一个连接该表与自身，以便产生1000个组合是这样的：

DROP VIEW IF EXISTS seq_0_to_999; 
CREATE VIEW seq_0_to_999 AS (
SELECT (a.seq + 10 * (b.seq + 10 * c.seq)) AS seq 
    FROM seq_0_to_9 a 
    JOIN seq_0_to_9 b 
    JOIN seq_0_to_9 c 
); 

我在这里写一些详细的内容在http://www.plumislandmedia.net/mysql/filling-missing-data-sequences-cardinal-integers/