我需要为Arraylist创建一个JSON对象。下面是代码创建一个JSON对象数组
public boolean submitOrder(ArrayList<OrderDetailsData> orderList) {
serUri = "lists.json";
method = "post";
JSONObject jsonObject = new JSONObject();
JSONObject json = new JSONObject();
JSONArray array = new JSONArray();
try {
for (int i = 0; i < orderList.size(); i++) {
json.put("orderno", orderList.get(i).getOrderNumber()
.toString());
json.put("tableno", orderList.get(i).getTableNumber()
.toString());
json.put("itemname", orderList.get(i).getItemName().toString());
json.put("amount", orderList.get(i).getAmount().toString());
json.put("ordstatus", orderList.get(i).getOrderStatus()
.toString());
array.put(json);
}
catch (JSONException je) {
return false;
}
try {
jsonObject.put("list", array);
} catch (JSONException je) {
return false;
}
WebServiceAsyncTask webServiceTask = new WebServiceAsyncTask();
webServiceTask.execute(serUri, method,jsonObject, this);
return true;
}
问题是它的创建对象与在每个位置的最后一行项目的详细信息。假如我的orderList有3行,那么创建的jsonObject有3行,但是所有3行都有第3行数据。看起来好像它的所有行的重写数据都是最新获取的行。我尝试了其他几种方法,但仍然没有得到期望的结果。请指教。谢谢。
JSON对象创建:
{"list":[{"amount":"10.50","orderno":"0220130826163623","quantity":"1","itemname":"Pollo Al Horno","tableno":"02","ordstatus":"placed"},{"amount":"10.50","orderno":"0220130826163623","itemname":"Pollo Al Horno","tableno":"02","ordstatus":"placed"},{"amount":"10.50","orderno":"0220130826163623","itemname":"Pollo Al Horno","tableno":"02","ordstatus":"placed"},{"amount":"10.50","orderno":"0220130826163623","itemname":"Pollo Al Horno","tableno":"02","ordstatus":"placed"},{"amount":"10.50","orderno":"0220130826163623","itemname":"Pollo Al Horno","tableno":"02","ordstatus":"placed"},{"amount":"10.50","orderno":"0220130826163623","itemname":"Pollo Al Horno","tableno":"02","ordstatus":"placed"},{"amount":"10.50","orderno":"0220130826163623","itemname":"Pollo Al Horno","tableno":"02","ordstatus":"placed"},{"amount":"10.50","orderno":"0220130826163623","itemname":"Pollo Al Horno","tableno":"02","ordstatus":"placed"}]}
上述目标在每行只有最后一个项目。
mh ...缺少{array.put(json);之后; –
感谢您指出这一点,但它已经在代码中。在粘贴时出现错字错误。 – Gaurav