我想解析并从Web服务获取值。问题是Web服务具有相同的元素名称标签,这些元素名称标签正在创建问题来解析,因为我想获取它们的值,但它们具有相同的名称。因此,我很难将它们提及为本地名称。Android:如何解析SAX解析器中的相同标记?
<countryBean>
<id>236</id>
<name>United State</name>
</countryBean>
<secutiryQuestion1>
<id>2</id>
<question>What was your dream job as a child?</question>
</secutiryQuestion1>
<secutiryQuestion2>
<id>4</id>
<question>What is the name, breed, and color of your pet?</question>
</secutiryQuestion2>
<stateBean>
<country>236</country>
<id>5</id>
<name>California</name>
</stateBean>
<statusBean>
<id>1</id>
<name>Active</name>
</statusBean>
我想获得ID标签和其他相邻标签的价值,如名称,问题在不同的变量。这里有5个Id标签。
我的类的代码是这样
public class XmlParser extends DefaultHandler {
public RestfullResponse tempResponse = null;
String currentValue = null;
int ServiceType =0;
@Override
public void startElement(String uri, String localName, String qName,
Attributes attributes) throws SAXException {
if(localName.equalsIgnoreCase("countryBean")){
tempResponse=new RestfullResponse();
}
}
/* (non-Javadoc)
* @see org.xml.sax.helpers.DefaultHandler#endElement(java.lang.String, java.lang.String, java.lang.String)
*/
@Override
public void endElement(String uri, String localName, String qName)
throws SAXException {
if(ServiceType == 1)
{
if(localName.equalsIgnoreCase("id")){
tempResponse.setCountryId(currentValue);
}
if(localName.equalsIgnoreCase("name")){
tempResponse.setCountryName(currentValue);
}
if(localName.equalsIgnoreCase("id")){
tempResponse.setStateId(currentValue);
}
if(localName.equalsIgnoreCase("question")){
tempResponse.setstateBean(currentValue);
}
if(localName.equalsIgnoreCase("Id")){
tempResponse.setStatusId(currentValue);
}
if(localName.equalsIgnoreCase("requestSuccess")){
tempResponse.setStatus(currentValue);
}
}
}
@Override
public void characters(char[] ch, int start, int length)
throws SAXException {
currentValue = new String(ch, start, length);
}
public RestfullResponse getResponse(){
return tempResponse;
}
}
请帮忙将它们存储在
String CountryName= "";
String CountryId = "";
String Statename = "";
String StateId ="";
String Status = "";
String StatusId = "";
String Username ="";
String SecurityQuestion = "";
String SecurityQuestionId = "";
感谢您的解决方案 – vuhung3990 2016-02-26 03:48:02