基于文件数据的两个字段的Python排序

Question

我尝试使用同一问题中接受的解决方案中描述的方法对给定here的数据进行排序。我列出了列表的列表，并尝试使用sorted方法尝试排序两次，而不是列表。但它没有奏效。我需要与上面链接中给出的输出相同的输出。这里是我的输出：

[['k3', '9.2603346875', '0.4639390435'], 
['K1', '4.1458078125', '0.5129700421'], 
['k2', '9.5360690625', '0.5481493305'], 
['k7', '9.8022878125', '0.562983695'], 
['k2', '6.319044375', '0.6469451082'], 
['k5', '7.2702040625', '0.6632701035'], 
['K1', '8.6394253125', '0.6690271589'], 
['K1', '8.025495625', '0.7561548244'], 
['k8', '5.44912125', '0.8532092538'], 
['k6', '7.73398625', '1.017231759'], 
['K1', '6.66228125', '1.0444456163'], 
['k4', '10.6868384375', '1.1287761798'], 
['k9', '7.5859665625', '1.276779643'], 
['K1', '6.48153375', '1.4176140292']] 

这里是我的代码：

path = "C:\\Chandresh_WORK\\data\\" 
inpfile = 'demo1.txt' 
mylist=[] 
from operator import itemgetter 
with open(path+inpfile,'r') as fid: 
    for line in fid:  
     myset = list(line.split()) 
     mylist.append(myset) 

mylist 
s=sorted(mylist,key=itemgetter(0))  
sorted(s,key=itemgetter(2)) 

Answer 1

你需要投你串数字类型，以避免的逐一排序，然后反转第二顺序排序标准，使其下降：

s = sorted(mylist,key=lambda x: (x[0], -float(x[2]))) 
#         ^invert sort order 

---

[['K1', '6.48153375', '1.4176140292'], 
['K1', '6.66228125', '1.0444456163'], 
['K1', '8.025495625', '0.7561548244'], 
['K1', '8.6394253125', '0.6690271589'], 
['K1', '4.1458078125', '0.5129700421'], 
['k2', '6.319044375', '0.6469451082'], 
['k2', '9.5360690625', '0.5481493305'], 
['k3', '9.2603346875', '0.4639390435'], 
['k4', '10.6868384375', '1.1287761798'], 
['k5', '7.2702040625', '0.6632701035'], 
['k6', '7.73398625', '1.017231759'], 
['k7', '9.8022878125', '0.562983695'], 
['k8', '5.44912125', '0.8532092538'], 
['k9', '7.5859665625', '1.276779643']]