2017-12-27 83 views
0

我有一个单选按钮列表。从取消选中的单选按钮删除班级名称

<input type="radio" name="capital" value="bratislava"> 
<input type="radio" name="capital" value="kiev"> 
<input type="radio" name="capital" value="prague"> 

单选按钮事件监听器类型change我添加一些class名这样的。

// Scope toggles 
var toggles = document.querySelectorAll('input[type=radio]'); 

// Accesses the toggles length property outside the loop and make the loop run faster 
var tL = toggles.length; 

// Loop-in for `toggles` length HTML collection 
for (var i = 0; i < tL; i++) { 

    // Store array-like objects in this variable 
    var currentToggle = toggles[i]; 

    // Run event listener method on `change` and refer to element using `this` keyword 
    currentToggle.addEventListener('change', function() { 

     // + ADD CLASS NAME 
     // Check if element is checked and if className isn't present 
     if (this.checked && !this.className.match(/(?:^|\s)class(?!\S)/)) { 
      // Add class name without removing/affecting existing values 
      this.className += " class"; 
     } 

     // - REMOVE CLASS NAME 
     else { 
      // Replace class with empty string 
      this.className = this.className.replace(/(?:^|\s)class(?!\S)/g , ''); 
     } 

    }) 

} 

这适用于复选框元素,但不适用于单选按钮组。 目标是在这个问题的标题。

为了解决它,我假设我应该在if语句中设置另一个循环,并为所有未经检查的收音机循环并删除该类?

+1

上 “点击” 事件添加监听器单选按钮,而不是 “变”。 –

+0

单选按钮只支持两个事件:'change'和'input'。 –

+1

这似乎更接近你的问题。看一看;希望它是帮助! https://stackoverflow.com/questions/8838648/onchange-event-handler-for-radio-button-input-type-radio-doesnt-work-as-one –

回答

1

下面的评论中提到的信息[OnChange event handler for radio button (INPUT type="radio") doesn't work as one value,你可以不用通过输入循环。

// Scope toggles 
 
var toggles = document.querySelectorAll('input[type=radio]'); 
 

 
// Accesses the toggles length property outside the loop and make the loop run faster 
 
var tL = toggles.length; 
 
var last = undefined; 
 
// Loop-in for `toggles` length HTML collection 
 
for (var i = 0; i < tL; i++) { 
 

 
    // Store array-like objects in this variable 
 
    var currentToggle = toggles[i]; 
 

 
    // Run event listener method on `change` and refer to element using `this` keyword 
 
    currentToggle.addEventListener('change', function() { 
 
    
 
     // + ADD CLASS NAME to current 
 
     // Check if element is checked and if className isn't present 
 
     if (this.checked && !this.className.match(/(?:^|\s)class(?!\S)/)) { 
 
      // Add class name without removing/affecting existing values 
 
      this.className += " class"; 
 
     } 
 

 
if(last === undefined){ 
 
    last = this; 
 
    return; 
 
} 
 
     // - REMOVE CLASS NAME 
 
     else { 
 
      // Replace class with empty string 
 
      last.className = last.className.replace(/(?:^|\s)class(?!\S)/g , ''); 
 
last = this; 
 
     } 
 

 
    }) 
 

 
}
<input type="radio" name="capital" value="bratislava">bratislava 
 
<input type="radio" name="capital" value="kiev">kiev 
 
<input type="radio" name="capital" value="prague">prague

+0

当取消选择不删除类 –

+1

@DomK,更新了答案。没有更新最后一个参考。 – gvmani

1

呀添加第二循环将解决您的probleme

var varName = document.querySelectorAll('input[type="radio"]'); 
 
for (var i = 0; i < varName.length; i++) varName[i].onchange = functionName; 
 

 
function functionName() { 
 
    for (var i = 0; i < varName.length; i++) { 
 
    if (varName[i] == this) varName[i].classList.add('selected'); 
 
    else varName[i].classList.remove('selected'); 
 
    } 
 
}
.selected { 
 
    background-color: green; 
 
}
<input type="radio" name="capital" value="bratislava"> 
 
<input type="radio" name="capital" value="kiev"> 
 
<input type="radio" name="capital" value="prague">

+0

为了简单起见如果不需要循环就像在接受的答案中一样,I/Browsers更喜欢它,如果可能的话。虽然很好的答案。 –