2014-03-07 222 views
0

这已被问很多,但我发现的答案似乎不工作,所以我在这里张贴,看看是否有人可以帮助。MYSQL日期前的日期

我有这个

$sql = "SELECT SQL_CALC_FOUND_ROWS *, UNIX_TIMESTAMP(order_date) AS order_date, UNIX_TIMESTAMP(order_expected) AS order_expected 
      FROM orders WHERE DATE(order_expected) BETWEEN NOW() AND DATE_ADD(NOW() - INTERVAL 7 DAY); 

$sql = "SELECT SQL_CALC_FOUND_ROWS *, UNIX_TIMESTAMP(order_date) AS order_date, UNIX_TIMESTAMP(order_expected) AS order_expected 
       FROM orders WHERE DATE(order_expected) BETWEEN NOW() AND DATE_ADD(NOW(), INTERVAL -7 DAY); 

所有字段名称是否正确,但既不似乎能够发展到今天前7天内得到其日期的值。

请帮忙。

伊恩

+0

交换日期周围。首先是较小的(即今天的七天) – Kickstart

回答

4

试试这个: -

SELECT SQL_CALC_FOUND_ROWS *, UNIX_TIMESTAMP(order_date) AS order_date, UNIX_TIMESTAMP(order_expected) AS order_expected 
FROM orders 
WHERE DATE(order_expected) BETWEEN DATE_ADD(NOW(), INTERVAL -7 DAY) AND NOW()