我是Django的初学者，面临着urls.py的语法错误

Question

这是我的个人/ urls.py。我一直在试图解决这个问题好几天。我知道这肯定是一个非常愚蠢的错误，但不胜感激。

from django.conf.urls import url, include 
from . import views 
urlpatterns = [ 
    url(r'^$',views.index, name='index'), 
    url(r'contact/',views.contact, name='contact') 
    url(r'about/',views.about, name='about') 
] 

这里是views.py

def index(request): 
    return render(request, 'personal/home.html') 

def contact(request): 
    return render(request, 'personal/basic.html', {'content':['https://www.facebook.com/arjunkashyap30']}) 

def about(request): 
    return render(request, 'personal/about.html', {'content': ["This is an abut 
page"]}) 

Answer 1

您在定义每个端点的最终忘记comma。

urlpatterns = [ 
    url(r'^$',views.index, name='index'), 
    url(r'contact/',views.contact, name='contact'), 
    url(r'about/',views.about, name='about'), 
]