我有一个很长的文件列表来处理,在python编程的10个步骤中,我试图创建一个makefile
来运行所有这些文件。出于某种原因,我不知道为什么,当我将它们作为下面的代码运行时,第二步后输出为空。当我运行它们时,一个接一个地调用,代码就可以工作,但是我在每一步中更改了输出的名称,或者更改了文件夹的输出,我不知道如何在makefiles
中生成它。我接受其他的建议除了makefiles
太(像pypelines
......我有点用shell命令丢失)如何在makefile中运行python并更改输出名称或目录?
我makefile
看起来像这样
zero::
for f in `ls data/wikiMaths/*.html`; do \
python src/maths/stripHtmlMaths.py $$f > $$f; \
done
one::
for f in `ls data/wikiMaths/*.html`; do \
python src/maths/Wiki2Text.py $$f > $$f; \
done
three::
for f in `ls data/wikiMaths/*.txt`; do \
python src/maths/striphtml.py $$f > $$f; \
done
four::
for f in `ls data/wikiMaths/*.txt`; do \
python src/maths/sipTrash.py $$f > $$f; \
done
five::
for f in `ls data/wikiMaths/*.txt`; do \
python src/maths/tagFormula.py $$f > $$f; \
done
six::
for f in `ls data/wikiMaths/*.txt`; do \
python src/maths/CountForm.py $$f > $$f; \
done
seven::
for f in `ls data/wikiMaths/*.txt`; do \
python src/maths/stripWhiteSpace.py $$f > $$f; \
done
eight::
for f in `ls data/wikiMaths/*.txt`; do \
python src/maths/Text2Xml.py $$f > $$f.xml; \
done
nine::
for f in `ls data/wikiMaths/*.xml`; do \
python src/maths/Separate.py $$f > $$f; \
done
我希望做的是一样的东西:
zero::
for f in `ls data/wikiMaths/*.html`; do \
python src/maths/stripHtmlMaths.py $$f > data/newFolder/$$f; \
done
one::
for f in `ls data/newFolder/*.html`; do \
python src/maths/Wiki2Text.py $$f > data/newFolderTwo/$$f.txt; \
done
,以取代:
python src/maths/stripHtmlMaths.py data/wikiMaths/file1.html > data/newFolder/file1.html
python src/maths/Wiki2Text.py data/newFolder/file1.html > data/newFolderTwo/file1.txt
我该如何连接其中的9个?...取决于行为,我将文件以行和其他文件的形式作为一个文本访问,因此更改脚本我可以读取文本作为文件存储为列表中的预览步骤 –