替换Python中字符的每个实例字符串

我有一个用户猜测字母的游戏。他们被显示为神秘作品的空白版本（例如，_____，_等于单词中的字符数）。该程序知道该单词，并且如果他们猜测的字母出现在神秘单词中，则需要替换该单词的空白版本中的每个索引。替换Python中字符的每个实例字符串

例如，如果玩家猜测“p”，单词是“河马”，他们将显示__pp_。但是，我的代码只会替换“p”的第一个实例，代之以__p__。

这会更容易处理列表问题吗？

mistakes = 0 
complete = False 
t = False 
words = ['cow','horse','deer','elephant','lion','tiger','baboon','donkey','fox','giraffe'] 

print("\nWelcome to Hangman! Guess the mystery word with less than 6 mistakes!") 


# Process to select word 
word_num = valid_number() 
word = words[word_num] 
#print(word) 
print("\nThe length of the word is: ", str(len(word))) 
attempt = len(word)*"_" 

# Guesses 
while not (mistakes == 6): 
    guess = valid_guess() 
    for letter in word: 
     if guess == letter: 
      print("The letter is in the word.") 
      position = word.index(guess) 
      attempt = attempt [0:position] + guess + attempt [position + 1:] 
      print("Letters matched so far: ", attempt) 
      t = True 
    while (t == False): 
     print("The letter is not in the word.") 
     print("Letters matched so far: ", attempt) 
     mistakes = mistakes + 1 
     hangMan = ["------------", "|   |", "|   O", "|  / |", "|   |", "|  / |\n|\n|"] 
     hang_man() 
     t = True 
    t = False

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2014-02-27 user3290553

answer = 'hippo' 
fake = '_'*len(answer) #This appears as _____, which is the place to guess 
fake = list(fake)  #This will convert fake to a list, so that we can access and change it. 
guess = raw_input('What is your guess? ') #Takes input 
for k in range(0, len(answer)): #For statement to loop over the answer (not really over the answer, but the numerical index of the answer) 
    if guess == answer[k] #If the guess is in the answer, 
     fake[k] = guess #change the fake to represent that, EACH TIME IT OCCURS 
print ''.join(fake) #converts from list to string

这种形式运行：

>>> What is your guess? 
p 
>>> __pp_

要遍历所有的一切，我没有使用index，因为index仅返回第一个实例：

>>> var = 'puppy' 
>>> var.index('p') 
0

所以要做到这一点，我不是通过字母来分析它，而是通过它的放置，使用一个不会将k作为每个字母，而是将其作为一个数字，以便我们可以有效地遍历整个字符串没有它只返回一个变量。

人们还可以使用re，但对于编程新手，最好是明白了什么是如何工作的，而不是从一个模块调用一组函数（除随机数的情况下，没有人希望让他们的自己的伪随机方程：D）

来源

2014-02-27 05:51:07

这几乎和我在hang子手游戏中所做的完全一样。 – sayantankhan

不错:)我也是... –

谢谢，这个很容易理解！当我得到第二个时，我会沿着这些路线实施一些事情。 – user3290553

基于Find all occurrences of a substring in Python：

import re 

guess = valid_guess() 
matches = [m.start() for m in re.finditer(guess, word)] 
if matches: 
    for match in matches: 
     attempt = attempt[0:match] + guess + attempt[match+1:] 
     print("Letters matched so far: ", attempt) 
else: 
    . 
    . 
    .

来源

2014-02-27 05:31:19

替换Python中字符的每个实例字符串

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