PHP的preg_match函数变量提取

Question

假设我有一个这样的字符串：

[$IMAGE[file_name|width|height]] 

我如何能匹配，并获得2个变量

$tag = "IMAGE" 
$param = "file_name|width|height" 

使用PHP的preg_match功能？

Answer 1

<?php 
$string = '[$IMAGE[file_name|width|height]]'; 
preg_match("/\[\\$(.*)\[(.*)\]\]/",$string,$matches); 

$tag = $matches[1]; 
$param = $matches[2]; 

echo "TAG: " . $tag; 
echo "<br />"; 
echo "PARAM: " . $param; 
?> 

Answer 2

$string = '[$IMAGE[file_name|width|height]]'; 
// Matches only uppercase & underscore in the first component 
// Matches lowercase, underscore, pipe in second component 
$pattern = '/\[\$([A-Z_]+)\[([a-z_|]+)\]\]/'; 
preg_match($pattern, $string, $matches); 

var_dump($matches); 
array(3) { 
    [0]=> 
    string(32) "[$IMAGE[file_name|width|height]]" 
    [1]=> 
    string(5) "IMAGE" 
    [2]=> 
    string(22) "file_name|width|height" 
} 

Answer 3

不使用preg_match，但效果一样好。

$var = '[$IMAGE[file_name|width|height]]'; 
$p1 = explode('[',$var); 
$tag = str_replace('$','',$p1[1]); 
$param = str_replace(']','',$p1[2]); 

echo $tag.'<br />'; 
echo $param;