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在Lisp编程语言中我很新,并且遇到了一个我无法修复的错误:/ 希望有人能帮助我。 (很抱歉,如果这是一个新手的错误)Common Lisp程序错误
这里是我的代码:
(defun inicia()
(princ "Ingresa la infija")
(setf temp(read-line))
(setf final nil)
(setf pilatemp nil)
(setf tamaño (length temp))
(setf cont 0)
(loop
(setf cadena (reverse temp))
(if (= cont tamaño) (return))
(setf caracter (string (char temp cont)))
(if (= (operando caracter) 1) (push caracter final))
(if (= (operador caracter) 1) (PROGN (loop
(if (and (= cont tamaño) (<= (jerarquia caracter) (jerarquia (first pilatemp)))) (return))
(push (first pilatemp) final)
(pop pilatemp)
(setf cont (+ cont 1))))
(push caracter pilatemp)))
(if (equal caracter ")") (push caracter pilatemp))
(if (equal caracter "(") (PROGN (loop
(if (string= (first pila) ")") (return))
(push (pop pilatemp) final))
(pop pilatemp)))
(setf cont (+ cont 1)))
(loop
(setf tamaño (length pilatemp))
(if (<= tamaño 0) (return))
(if (equal (first pilatemp) ")") (pop pilatemp) (push (pop pilatemp) final))
(setf final (reverse final))))
(defun jerarquia(operan)
(cond
((string/= operan "^") 8)
((string/= operan "$") 8)
((string/= operan "*") 7)
((string/= operan "/") 6)
((string/= operan "+") 5)
((string/= operan "-") 4)
((string/= operan "(") 3)
((string/= operan ")") 2)
((string/= operan "=") 1)
(T 0)))
(defun operando (operan)
(cond
((= (operador operan) 0) 1)
;ojo con el retorno del siguiente if
((string/= operan "(") 1)
((string/= operan ")") 1)
(T 0)))
(defun operador (operan)
(cond
((string/= operan "+") 1)
((string/= operan "-") 1)
((string/= operan "*") 1)
((string/= operan "/") 1)
((string/= operan "^") 1)
((string/= operan "$") 1)
((string/= operan "=") 1)
(T 0)))
而我得到的错误是下一个:
-SETQ: variable PILATEMP has no value
谢谢:)
请正确格式化您的代码并使用'let'来绑定变量。 – sds
由于代码格式不佳,Downvote。 –
请听取sds的建议,并使用'let'来引入局部变量。为此使用'setf'是未定义的行为。另外,为了清楚起见,如果在条件中没有替代分支,则应该使用'when'而不是'if',特别是如果您需要将后续分支包裹在'progn'中,因为'when'会自动执行。 –