2011-11-16 73 views
5

我不确定如何使用SQL从RSS提要中获取dc:creator的值。 这是我的XML/RSS饲料:使用SQL XML获取dc:creator的价值

<rss xmlns:dc="http://purl.org/dc/elements/1.1/" version="2.0"> 
<channel> 
    <title>Foobar RSS</title> 
    <link>http://www.foobar.com/</link> 
    <description>RSS feed</description> 
    <language>en</language> 
    <ttl>15</ttl> 
    <item> 
     <title>This is my title</title> 
     <link>http://www.foobar.com/link/blabla</link> 
     <description>Bla..bla..bla..</description> 
     <dc:creator>John Doe</dc:creator> 
     <guid isPermaLink="false">00082EA751F1D905DE00E7CFA2417DA9</guid> 
     <pubDate>Wed, 26 Oct 2011 00:00:00 +0200</pubDate> 
    </item> 
</channel> 
</rss> 

在我的SQL我使用这样得到的数值 - 例如用于pubdate的我用的是这样的:

DECLARE @xml XML 
SET @xml = cast('my rss feed here' AS xml) 

SELECT 
convert(datetime,substring(T.nref.value('pubDate[1]','nvarchar(100)'),6,20)) as pubdate, 
FROM @xml.nodes('//item') AS T(nref) 

这工作得很好,但是,当我试图让DC:创值“李四”,以下只是给了我一个错误:

SELECT 
    T.nref.value('dc:creator','nvarchar(100)') as creator 
FROM @xml.nodes('//item') AS T(nref) 

    error: 
    XQuery [value()]: The name "dc" does not denote a namespace. 

我需要能够选择从RSS源多列。任何人都可以提供一个解决方案或方向来获得dc:creator的价值吗?

我还有一个问题 - 如果你在子选择中做了它,你将如何构造代码?

E.g. 
INSERT INTO RSSResults (ID, pubDate) 
SELECT @ID, tbl.pubDate FROM (  

;WITH XMLNAMESPACES('http://purl.org/dc/elements/1.1/' AS dc) 
    SELECT 
     RSS.Item.value('(dc:creator)[1]', 'nvarchar(100)') as pubDate 
    FROM 
     @xml.nodes('/rss/channel/item') as RSS(Item)) AS tbl 

代码在“; WITH XMLNAMESPACES”中断。是否有可能以某种方式直接在语句中包含名称空间?

回答

8

尝试这样:

DECLARE @xml XML 
SET @xml = cast('my rss feed here' AS xml) 

;WITH XMLNAMESPACES('http://purl.org/dc/elements/1.1/' AS dc) 
SELECT 
    @xml.value('(rss/channel/item/dc:creator)[1]', 'nvarchar(100)') 

如果您需要捕捉多个项目 - 试试这个:

DECLARE @xml XML 
SET @xml = cast('my rss feed here' AS xml) 

;WITH XMLNAMESPACES('http://purl.org/dc/elements/1.1/' AS dc) 
SELECT 
    RSS.Item.value('(dc:creator)[1]', 'nvarchar(100)') 
FROM 
    @xml.nodes('/rss/channel/item') as RSS(Item)