检索数据库SQLite的Android的另一个图像

Question

我是新来的：d

我在我的Android应用程序检索数据库SQLite的图像，但是当我试图让其他图像，图像还只是同以前一样。它总是retrive从第1行的形象，我不知道为什么

这是我的代码

public void findAlphabet(View view) { 
    try { 
     db = kamusTI.getWritableDatabase(); 
     String sql = "SELECT * FROM kamusti WHERE istilah LIKE '" 
       + editAlphabet.getText().toString() + "%' ORDER BY istilah"; 
     cursor = db.rawQuery(sql, null);    
     adapter2 = new SimpleCursorAdapter(this, 
       android.R.layout.simple_list_item_2, cursor, new String[] { 
         "istilah", "definisi" }, new int[] { 
         android.R.id.text1, android.R.id.text2 }); 
     listView2.setAdapter(adapter2); 
     listView2.setTextFilterEnabled(true); 
     String sql1 = "SELECT COUNT(istilah) FROM kamusti WHERE istilah LIKE '" 
       + editAlphabet.getText().toString() + "%' ORDER BY istilah"; 
     cursor = db.rawQuery(sql1, null); 
     cursor.moveToFirst(); 

     cur = db.query("kamusti", null, null, null, null, null, null); 
     cur.moveToFirst(); 
    // cur.moveToPosition(0); 
     byte[] im = cur.getBlob(3); 
     // ByteArrayInputStream imagestream = new ByteArrayInputStream(im); 
      Bitmap imagestream = BitmapFactory.decodeByteArray(im, 0, im.length); 
     // Bitmap image = BitmapFactory.decodeStream(imagestream); 
      img = (ImageView) findViewById (R.id.gambar); 
      img.setImageBitmap(imagestream); 
     hasilCari.setText("Hasil Pencarian : " + cursor.getInt(0)); 
    } catch (SQLException e) { 
     hasilCari.setText(e.toString()); 
    } 
} 

我没有任何想法如何解决这一问题。当我尝试在我的应用程序中查找另一个字母时，图像将始终显示在数据库的第1行中。 请帮我:)

*我的英文不好

Answer 1

哦，对不起的人，我很抱歉，但我必须说的：你的代码是真正可怕的......

它不是在举办所有，但也许...不应该byte[] im = cur.getBlob(3);是byte[] im = cursor.getBlob(3);而不是？

编辑：试评第二和第三个疑问，因为他们似乎无用，使“小人” - 我建议>“光标”的变化：

public void findAlphabet(View view) { 
     try { 
      db = kamusTI.getWritableDatabase(); 
      String sql = "SELECT * FROM kamusti WHERE istilah LIKE '" 
        + editAlphabet.getText().toString() + "%' ORDER BY istilah"; 
      cursor = db.rawQuery(sql, null);    
      adapter2 = new SimpleCursorAdapter(this, 
        android.R.layout.simple_list_item_2, cursor, new String[] { 
          "istilah", "definisi" }, new int[] { 
          android.R.id.text1, android.R.id.text2 }); 
      listView2.setAdapter(adapter2); 
      listView2.setTextFilterEnabled(true); 
//   String sql1 = "SELECT COUNT(istilah) FROM kamusti WHERE istilah LIKE '" 
//     + editAlphabet.getText().toString() + "%' ORDER BY istilah"; 
//   cursor = db.rawQuery(sql1, null); 
       cursor.moveToFirst(); 

//   cur = db.query("kamusti", null, null, null, null, null, null); 
//   cur.moveToFirst(); 
     // cur.moveToPosition(0); 
      byte[] im = cursor.getBlob(3); 
      // ByteArrayInputStream imagestream = new ByteArrayInputStream(im); 
       Bitmap imagestream = BitmapFactory.decodeByteArray(im, 0, im.length); 
      // Bitmap image = BitmapFactory.decodeStream(imagestream); 
       img = (ImageView) findViewById (R.id.gambar); 
       img.setImageBitmap(imagestream); 
      hasilCari.setText("Hasil Pencarian : " + cursor.getInt(0)); 
     } catch (SQLException e) { 
      hasilCari.setText(e.toString()); 
     } 
    }