1
我有一个足球比赛的数据库。保存匹配的表使用外键来存储团队(分别为team1和team2 - 主机和来宾)。我需要将结果与团队表中的结果结合起来。在表中两次相同的外键
match:
+-----------------+------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------------+------------------+------+-----+---------+----------------+
| match_id | int(10) unsigned | NO | PRI | NULL | auto_increment |
| championship_id | int(10) unsigned | YES | MUL | NULL | |
| team1_id | int(10) unsigned | YES | MUL | NULL | |
| team2_id | int(10) unsigned | YES | MUL | NULL | |
| factor_1 | decimal(4,2) | YES | | NULL | |
| factor_x | decimal(4,2) | YES | | NULL | |
| factor_2 | decimal(4,2) | YES | | NULL | |
| goals_team_1 | tinyint(4) | YES | | NULL | |
| goals_team_2 | tinyint(4) | YES | | NULL | |
| match_date | date | YES | | NULL | |
+-----------------+------------------+------+-----+---------+----------------+
team:
+---------+------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+---------+------------------+------+-----+---------+----------------+
| team_id | int(10) unsigned | NO | PRI | NULL | auto_increment |
| name | varchar(32) | YES | | NULL | |
+---------+------------------+------+-----+---------+----------------+
我的猜测是,使用此查询,但它是无效的:
SELECT match.match_id, team.name, team.name, match.match_date
FROM `match`
INNER JOIN `team`
ON match.team1_id=team.team_id,
match.team2_id=team.team_id
使用两个团队而不是一个 – Ejaz
您的查询不是无效的方式。它只会返回0行(除非你有一些团队与自己对抗的比赛)! –