在视图控制器之间传递数据segue

我的第一个视图控制器AllAthletes是我所有核心数据实体的可用视图。它显示实体“运动员”，它的属性在字幕样式表单元格中，比如名字等。当你点击一个视图单元格时，我希望这个视图控制器传递被选中的实体的信息， m不确定如何将此信息（indexpath的managedobject，entity，properties等）传递给详细视图控制器。有人能指点我正确的方向吗？在视图控制器之间传递数据segue

allathletes.m

-(void)viewWillAppear:(BOOL)animated{ 
    AppDelegate *appDelegate = [[UIApplication sharedApplication] delegate]; 
    _managedObjectContext = [appDelegate managedObjectContext]; 

    NSFetchRequest *request = [[NSFetchRequest alloc] init]; 
    NSEntityDescription *athlete = [NSEntityDescription entityForName:@"Athlete" inManagedObjectContext:_managedObjectContext]; 
    [request setEntity:athlete]; 
    NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"first" ascending:YES]; 
    NSArray *sortDescriptors = [[NSArray alloc]initWithObjects:sortDescriptor, nil]; 
    [request setSortDescriptors:sortDescriptors]; 

    NSError *error = nil; 
    NSMutableArray *mutableFetchResults = [[_managedObjectContext executeFetchRequest:request error:&error] mutableCopy]; 
    if (mutableFetchResults == nil){ 
     //handle error 
    } 
    [self setAthleteArray:mutableFetchResults]; 
    [self.tableView reloadData]; 
} 



//this is what I have so far 
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender 
{ 
    if ([segue.identifier isEqualToString:@"setAthlete"]) { 
     NSIndexPath *indexPath = [self.tableView indexPathForSelectedRow]; 
     AthleteDetail *destViewController = segue.destinationViewController; 
    } 
} 

//i was also thinking something like this? 
- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath 
{ 
    UIViewController* detailViewController = [self.storyboard instantiateViewControllerWithIdentifier:@"DetailViewController"]; 
    NSMutableString *object = thisArray[indexPath.row]; 
    detailViewController.passedData = object; 
    [self.navigationController pushViewController:detailViewController animated:YES]; 
}

，它会使你得到第二控制器AthleteDetail。感谢您的时间。

来源

2013-08-01 Josue Espinosa

那么，你需要使用'performSegueWithIdentifier：sender：'。您现在正在手动推送。 – Desdenova

目前尚不清楚你的具体问题是什么。如何做到这一点在“用于iOS的表格视图编程指南”的“在表格视图中浏览数据层次结构”一节中进行了说明。阅读它，如果你仍然不明白，请提出一个更具体的问题。 – rdelmar

@rdelmar更好吗？ –

你在混合两个不同的概念。取而代之的

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath 
{ 
    UIViewController* detailViewController = [self.storyboard instantiateViewControllerWithIdentifier:@"DetailViewController"]; 
    NSMutableString *object = thisArray[indexPath.row]; 
    detailViewController.passedData = object; 
    [self.navigationController pushViewController:detailViewController animated:YES]; 
}

你应该这样做

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath 
{ 
    [self performSegueWithIdentifier:YOUR_SEGUE_IDENTIFIER sender:self];   
}

然后：

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender 
{ 
    if ([segue.identifier isEqualToString:YOUR_SEGUE_IDENTIFIER]) { 
     NSIndexPath *indexPath = [self.tableView indexPathForSelectedRow]; 
     AthleteDetail *destViewController = segue.destinationViewController; 
     // set whatever you want here in your destination view controller 
     destViewController.passedData = object; 
    } 
}

，并确保您的Segue公司是推送Segue公司。

来源

2013-08-01 14:36:47

在视图控制器之间传递数据segue

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