重命名文件名在表

Question

我有一个表作为

'310', 'D', '1', '0', 'Clowns.jpg', ?, '63527560196' 
'311', 'D', '1', '1', 'Clowns_102_x_102.jpg', ?, '63527560197' 
'312', 'D', '1', '1', 'Clowns_45_x_45.jpg', ?, '63527560197' 
'313', 'D', '1', '1', 'Clowns_80_x_80.jpg', ?, '63527560197' 
'314', 'D', '1', '1', 'Clowns_120_x_120.jpg', ?, '63527560198' 
'315', 'D', '1', '1', 'Clowns_180_x_180.jpg', ?, '63527560198' 
'316', 'D', '1', '1', 'Clowns_300_x_300.jpg', ?, '63527560198' 

我想叫小丑文件重命名为小丑，这样数据看起来像这样

'310', 'D', '1', '0', 'Clowning.jpg', ?, '63527560196' 
'311', 'D', '1', '1', 'Clowning_102_x_102.jpg', ?, '63527560197' 
'312', 'D', '1', '1', 'Clowning_45_x_45.jpg', ?, '63527560197' 
'313', 'D', '1', '1', 'Clowning_80_x_80.jpg', ?, '63527560197' 
'314', 'D', '1', '1', 'Clowning_120_x_120.jpg', ?, '63527560198' 
'315', 'D', '1', '1', 'Clowning_180_x_180.jpg', ?, '63527560198' 
'316', 'D', '1', '1', 'Clowning_300_x_300.jpg', ?, '63527560198' 

所以，我想这个

UPDATE new_images 
SET 
filespec = 'clowns100' + MID(filespec, 7, LENGTH(filespec) - 6); 

但是我得到了

错误代码：1292截断不正确DOUBLE值： 'clowns100'

Answer 1

使用REPLACE

UPDATE new_images SET filespec = REPLACE(filespec, 'Clowns','Clowning') 

• MySQL Replace (String Function)

UPDATE 1

为您的查询相当于MySQL的代码是

UPDATE new_images 
SET filespec = CONCAT('clowns100', MID(filespec, 7, CHAR_LENGTH(filespec) - 6)); 

Answer 2

您可以使用子在SQL

UPDATE new_images SET filespec = 'Clowning'+substring('Clowns.jpg', 7, len('Clowns.jpg') - 6) where filespec like 'Clowns%'