2017-05-23 48 views
0

我的模型看起来是这样的:Django的ORM过滤

Person(model.Models): 
    name = model.CharField(max_length=32) 
    date_added = models.DateTimeField(auto_now_add=True) 

Note(model.Models): 
    person = model.ForeignKey(Person) 
    action = model.CharField(max_length=32, default='call) 
    date_added = models.DateTimeField(auto_now_add=True) 
    owner = model.ForeignKey(User) 

我的观点:

def get_working_persons(self): 
    relevant_actions = ['call', 'meeting', ...] 
    query = Q(action__in=relevant_note_actions) | Q(date_added__range=[fourteen_days_ago, now]) 
    get_current_person_notes = Note.objects.filter(query).exclude(~Q(owner=request.user)).values('owner', 'action', 'person') 

这返回的音符,每个人拥有所有的笔记中列出的清单,被贴内date_added__range。如何获得该日期范围内每个人的最后一张纸条,并符合其他标准?

回答

1
Note.objects.filter(query).exclude(~Q(owner=request.user)).values('owner', 'action', 'person').first() 

将返回查询集的顶部对象 或

Note.objects.filter(query).exclude(~Q(owner=request.user)).values('owner', 'action', 'person').last() 

将返回查询集

或最迟在字段名的最后一个对象

Note.objects.filter(query).exclude(~Q(owner=request.user)).values('owner', 'action', 'person').latest('field_name') 
+0

非常感谢。从我所能看到的情况来看,这只会返回最后一个对象。我想获得每个人的最后一个对象。 因此类似于: 'Select * from note where date_added between now和fourteen_days_ago GROUP BY'person'' –

+0

@ 5h3z4n查看https://docs.djangoproject.com/zh/1/11/topics/db/聚合/ –

+0

@ pawel.ad这看起来像我需要!谢谢 –