在另一列中筛选出包含特定值的ID

Question

因此，我想从这两个表中筛选出ID'union all'ed。基本上，如果ID包含某个名称，我想将它们过滤出查询。下面是一个例子

ID,Name 

1,Mark 
1,John 
2,Peter 
2,Matt 
3,Henry 
3,Matt 
4,John 
4,Olaf 

所以我不希望包括含有“马特”，意思是我想出来完全过滤掉的ID 2和3的ID。

使用类似：

select * 
from name.table 
where name not like 'Matt' 

似乎只筛选出的行。

Answer 1

你会想要做这样的事情：

select * from table where id not in(
    select Id from table where name like '%Matt%' 
) 

这不包括含马特

排除这等于行马特

select * from table where id not in(
    select Id from table where name ='Matt' 
) 

Answer 2

使用not exists：

select n.* 
from names n 
where not exists (select 1 from names n2 where n2.id = n.id and n2.name = 'Matt') 

Answer 3

试试这个：

SELECT * FROM TableName 
WHERE ID NOT IN (SELECT ID FROM TableName WHERE name='Matt') 

OR使用LIKE：

SELECT * FROM TableName 
WHERE ID NOT IN (SELECT ID FROM TableName WHERE name LIKE '%Matt%') 

对于不同的值：

SELECT DISTINCT ID FROM TableName 
WHERE ID NOT IN (SELECT ID FROM TableName WHERE name='Matt') 

Answer 4

SELECT * FROM names 
WHERE ID NOT IN 
(SELECT ID FROM names WHERE name='Matt') 

Answer 5

(SELECT Column(s) FROM Table1) 
UNION ALL 
(SELECT Column(s) FROM Table2) 
EXCEPT 
(SELECT Column(s) FROM Table1 where name = 'Matt') 
EXCEPT 
(SELECT Column(s) FROM Table2 where name = 'Matt') 

名行