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我有一个使用我拥有的WSDL生成的客户端。当我试图连接到这个WebService的,我得到以下错误:Apache CXF WebServices客户端错误
javax.xml.ws.soap.SOAPFaultException: An error occurred when verifying security for the message.
at org.apache.cxf.jaxws.JaxWsClientProxy.invoke(JaxWsClientProxy.java:161)
承载WebService的实际服务器期望包含安全头就像一个SOAP消息:
<soapenv:Header>
<o:Security s:mustUnderstand="1" xmlns:o="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd">
<o:UsernameToken u:Id="XXXX">
<o:Username>XXXX</o:Username>
<o:Password Type="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordText">XXXX</o:Password>
</o:UsernameToken>
</o:Security>
</soapenv:Header>
如何获得这与我的SOAP消息一起发出请求时生成吗?这是我在我的代码中调用WebService所做的事情:
val factory = new org.apache.cxf.jaxws.JaxWsProxyFactoryBean()
factory.setServiceClass(classOf[MyWebService])
// if there is an address, then let's set it!
factory.setAddress("https://my/server/address/MyWebService.svc")
// log incoming and outgoing
factory.getInInterceptors.add(new org.apache.cxf.interceptor.LoggingInInterceptor())
factory.getOutInterceptors.add(new org.apache.cxf.interceptor.LoggingOutInterceptor())
val myServiceClient = factory.create().asInstanceOf[MyWebService]
myServiceClient.myMethod("param")
有什么建议吗?