我有一个MySQL查询,它直接在我的本地MySQL数据库上执行时工作正常,但通过PHP执行时显示不同的结果。PHP和MySQL显示不同的结果与相同的查询
SELECT a.id, a.title, a.public, a.sysstamp, a.password, t.thumbURL, t.count
FROM 0_lychee_albums AS a
LEFT JOIN (SELECT id, album, thumbURL,
@num := IF(@group = album, @num + 1, 0) AS count,
@group := album AS dummy
from 0_lychee_photos
WHERE album != 0
ORDER BY album, star DESC) AS t ON a.id = t.album
WHERE count <= 2 OR count IS NULL;
或作为一衬垫:
SELECT a.id, a.title, a.public, a.sysstamp, a.password, t.thumbURL, t.count FROM 0_lychee_albums AS a LEFT JOIN (SELECT id, album, thumbURL, @num := IF(@group = album, @num + 1, 0) AS count, @group := album AS dummy FROM 0_lychee_photos WHERE album != 0 ORDER BY album, star DESC) AS t ON a.id = t.album WHERE count <= 2 OR count IS NULL;
其结果是:
| id | title | public | sysstamp | password | thumbURL | count |
| 71 | [Import] 01 | 0 | 1415091268 | NULL | cad008943372d984a9b74378874128f8.jpeg | 0 |
| 72 | [Import] 9n4| 0 | 1415091268 | NULL | 7b832b56f182ad3403521589e2815f67.jpeg | 0 |
| 72 | [Import] 9n4| 0 | 1415091268 | NULL | f058f379ce519f1d8a2ff8c0f5003631.jpeg | 1 |
| 72 | [Import] 9n4| 0 | 1415091268 | NULL | a4d59377bed059e3f60cccf01a69c299.jpeg | 2 |
| 73 | Untitled | 0 | 1415114200 | NULL | NULL | NULL |
PHP的结果:
| id | title | public | sysstamp | password | thumbURL | count |
| 71 | [Import] 01 | 0 | 1415091268 | NULL | cad008943372d984a9b74378874128f8.jpeg | 0 |
| 72 | [Import] 9n4| 0 | 1415091268 | NULL | 7b832b56f182ad3403521589e2815f67.jpeg | 0 |
| 72 | [Import] 9n4| 0 | 1415091268 | NULL | f058f379ce519f1d8a2ff8c0f5003631.jpeg | 0 |
| 72 | [Import] 9n4| 0 | 1415091268 | NULL | a4d59377bed059e3f60cccf01a69c299.jpeg | 0 |
| 72 | [Import] 9n4| 0 | 1415092318 | NULL | 7b832b56f182ad3403521589e2815f67.jpeg | 0 |
| 72 | [Import] 9n4| 0 | 1415092369 | NULL | cad008943372d984a9b74378874128f8.jpeg | 0 |
| 72 | [Import] 9n4| 0 | 1415092369 | NULL | 84030a64a1f546e223e6a46cbf12910f.jpeg | 0 |
| 73 | Untitled | 0 | 1415114200 | NULL | NULL | NULL |
一个)count
不增加像它应该
b)因为a)它显示的行数比它应该多(应该限制为每个ID 3)
我检查过多次,两个查询都完全一样。没有用户输入或PHP中的任何差异。
我已经检查了similar questions,但没有帮助。以下查询在MySQL和PHP上都显示相同的结果:
SHOW VARIABLES LIKE 'character_set%';
SHOW VARIABLES LIKE 'collation%';
是否有人知道这个问题的差异?
编辑与进一步的信息:
$database = new mysqli($host, $user, $password, $database);
$query = "SELECT a.id, a.title, a.public, a.sysstamp, a.password, t.thumbURL, t.count FROM 0_lychee_albums AS a LEFT JOIN (SELECT id, album, thumbURL, @num := IF(@group = album, @num + 1, 0) AS count, @group := album AS dummy FROM 0_lychee_photos WHERE album != 0 ORDER BY album, star DESC) AS t ON a.id = t.album WHERE count <= 2 OR count IS NULL";
$albums = $database->query($query);
while ($album = $albums->fetch_assoc()) { print_r($album); }
我也有和没有执行查询之前,以下试了一下:
$database->set_charset('utf8');
$database->query('SET NAMES utf8;');
num_rows()函数告诉你什么? – 2014-11-05 10:56:15
这是不可能的,一个班轮或格式的SQL造成如此大的差异,你应该检查你的代码。我觉得有些东西在那里。只有你的查询差异是',星形DESC',但我不认为这将使差异 – 2014-11-05 11:10:37
确保你的PHP代码指向相同的数据库,你正在运行此查询 – 2014-11-05 11:15:08