mysqli准备语句错误（bind_param）

Question

这是一个this question，但它没有得到答复。所以我告诉我的故事！

<?php 

include("connect.php"); 

$keyz = $_GET['id']; 

mysqli_real_escape_string($db, $keyz); 

if(!empty($_POST)){ 

    $query = $db->prepare("UPDATE talents SET (firstName,lastName,gender,dob,email,streetAddress,phoneNumber,city,state,country,zip,eyeColor,hairColor,height,weight,chest,waist,hips,dressSize,shoeSize) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?) WHERE pk = ?"); 
    $query->bind_param('sssssssssssssssssssss',$_POST['firstName'],$_POST['lastName'],$_POST['gender'],$_POST['dob'],$_POST['email'],$_POST['streetAddress'],$_POST['phoneNumber'],$_POST['city'],$_POST['state'],$_POST['country'],$_POST['zip'],$_POST['eyeColor'],$_POST['hairColor'],$_POST['height'],$_POST['weight'],$_POST['chest'],$_POST['waist'],$_POST['hips'],$_POST['dressSize'],$_POST['shoeSize'],$keyz); 
    $query->execute(); 
    $db->close(); 

    print_r($_POST['firstName'] . " " . $_POST['lastName'] . " has been updated."); 

} 

$query = "SELECT * FROM talents WHERE pk = " . $keyz; 

if(!$result = $db->query($query)){ 
    die('There was an error running the query [' . $db->error . ']'); 
} 

while($row = $result->fetch_assoc()){ 

?> 
. 
. 
. 
On to populate edit form 

Connect.php（这是我的本地开发机器上）：

$db = new mysqli('localhost', 'root', '', '[password]'); 

if($db->connect_errno > 0){ 
    die('Unable to connect to database [' . $db->connect_error . ']'); 
} 

而我得到的错误：

Fatal error: Call to a member function bind_param() on a non-object in C:\Program Files (x86)\EasyPHP-DevServer-13.1VC9\data\localweb\FuseTalent\editTalent.php on line 80

我试过在建议什么danzan另一个问题和var_dump $查询，但它返回的是bool(false)。

我在做什么错？我从另一个工作页面复制/粘贴/调整了代码。

Answer 1

mysqli->prepare()如果出现问题，则返回FALSE。这将导致调用{FALSE}->bindParam(...);，这将解释错误消息call to a member function ... on a non-object。
添加更多的错误处理您的脚本

$query = $db->prepare("UPDATE talents SET ..."); 
if (!$query) { 
    // something went wrong 
    // $db->errno and $db->error should contain more information about the error 
    // see http://docs.php.net/manual/en/mysqli.error.php 
    ... 
} 

也看一看的MySQL UPDATE syntax。这是

UPDATE talents SET 
firstName=?, 
lastName=?, 
... 
WHERE 
... 

的