从插入到/选择

Question

我正在使用SQL Server 2012中的脚本（作为后端到传统ASP页面）从我的初始表（aaa_test_ap）中选择所有行并将它们分配到我的3个其他表中（aaa_test_users ，aaa_test_users_positions和aaa_test_users_education）。

我想在同一个查询中将aaa_test_users.ID一行插入到其中，以便在其他两个表插入中使用它们的FK（User_ID）。

在一个查询中可以通过INSERT INTO方法获得身份吗？

我试过使用SCOPE_Identity()，但它只返回最后一个值。

使用OUTPUT方法，我将如何利用它生成的表值，以便将第一个插入语句生成的值插入到接下来的两个语句中，每个语句都在正确插入的行中？

一，表：

CREATE TABLE [dbo].[aaa_test_sp] 
(
    [ID] [int] IDENTITY(1,1) NOT NULL, 
    [UserName] [nvarchar](50) NULL, 
    [first_name] [nvarchar](50) NULL, 
    [last_name] [nvarchar](50) NULL, 
    [position] [nvarchar](50) NULL, 
    [phone] [nvarchar](50) NULL, 
    [education] [nvarchar](50) NULL, 
    [ListID] [int] NULL, 

    CONSTRAINT [PK_aaa_test_sp] 
     PRIMARY KEY CLUSTERED ([ID] ASC) 
) ON [PRIMARY] 
GO 

CREATE TABLE [dbo].[aaa_test_users] 
(
    [UserID] [int] IDENTITY(1,1) NOT NULL, 
    [UserName] [nvarchar](50) NULL, 
    [first_name] [nvarchar](50) NULL, 
    [last_name] [nvarchar](50) NULL, 

    CONSTRAINT [PK_aaa_test_users] 
     PRIMARY KEY CLUSTERED ([UserID] ASC) 
) ON [PRIMARY] 
GO 

CREATE TABLE [dbo].[aaa_test_users_positions] 
(
    [ID] [int] IDENTITY(1,1) NOT NULL, 
    [UserID] [int] NULL, 
    [position] [nvarchar](50) NULL, 
    [phone] [nvarchar](50) NULL, 

    CONSTRAINT [PK_aaa_test_users_positions] 
     PRIMARY KEY CLUSTERED ([ID] ASC) 
) ON [PRIMARY] 
GO 

CREATE TABLE [dbo].[aaa_test_users_education] 
(
    [ID] [int] IDENTITY(1,1) NOT NULL, 
    [UserID] [int] NULL, 
    [education] [nvarchar](50) NULL, 

    CONSTRAINT [PK_aaa_test_users_education] 
     PRIMARY KEY CLUSTERED ([ID] ASC) 
) ON [PRIMARY] 
GO 

这是我一直在努力查询：

--declare @NewUserID nvarchar(50) 
DECLARE @InsertOutput1 table (UserID nvarchar(50)); 

--insert, first, rows from sp to users, and get the autoNumber'ed ID, 
--"NewUserID" 
INSERT INTO aaa_test_users (UserName, first_name, last_name) 
OUTPUT inserted.UserID INTO @InsertOutput1 
    SELECT 
     UserName, first_name, last_name 
    FROM aaa_test_sp 
    WHERE (ListId = '1') 

--select * from @InsertOutput1 
--SELECT SCOPE_IDENTITY() As NewUserID 
--set @NewUserID=(SELECT SCOPE_IDENTITY()) 

--now that the "NewUserID" has been generated, 
--insert it, along with other columns, 
--into the 'users_positions' table. 
--print 'new user id is ' + @NewUserID 
INSERT INTO aaa_test_users_positions (UserID, position, phone) 
    (SELECT 
     @NewUserID, position, phone 
    FROM aaa_test_sp 
    WHERE (ListId = '1') 
    ) 

--now that the "NewUserID" has been generated, 
--insert it, along with other columns, 
--into the 'users_education' table 
--print @NewUserID 
INSERT INTO aaa_test_users_education (UserID, education) 
    (SELECT @NewUserID, education 
    FROM aaa_test_sp 
    WHERE (ListId = '1')) 

Answer 1

您加入到新的ID是该表。

至于第二个插入一个例子：

INSERT INTO aaa_test_users_positions(UserID, position, phone) 
    SELECT io.UserID, position, phone 
    FROM aaa_test_sp cross join 
     @InsertOutput1 io 
    WHERE ListId = '1'; 

注：鉴于你的结构，有可能是在@InsertOutput1只有一行，所以比预期这不应该产生更多的行。