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home.html的文件：jQuery Mobile的表单提交问题，PHP的警告：（预计参数1是mysqli的，空给出）
两个简单的JQ移动网页具有页眉和页脚固定。表格在第一页。我现在没有添加任何“密码必须匹配确认密码”的规定。我只想让它首先与数据库一起工作，即存储在数据库中。
<!DOCTYPE html>
<html>
<head>
<!-- Include meta tag to ensure proper rendering and touch zooming -->
<meta name="viewport" content="width=device-width, initial-scale=1">
<!-- Include jQuery Mobile stylesheets -->
<link rel="stylesheet" href="https://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.css">
<link rel="stylesheet" type="text/css" href="https://example.net/Login/styles.css">
<!-- Include the jQuery library -->
<script src="https://code.jquery.com/jquery-1.11.3.min.js"></script>
<!-- Include the your Ajax-ify file -->
<script type="text/javascript" src="https://example.net/Login/functions.js"></script>
<!-- Include the jQuery Mobile library -->
<script src="https://code.jquery.com/mobile/1.4.5/jquery.mobile-1.4.5.min.js"></script>
</head>
<body>
<!-- -->
<!-- Page One starts here -->
<!-- -->
<div data-role="page" id="pageone">
<div data-role="header" data-theme="b">
<h1>Welcome</h1>
</div>
<div data-role="main" class="ui-content">
<br>
<br>
<!-- Form starts here -->
<form id="NewForm" method="post" action="include.php">
<label>Username</label>
<input type="text" name="username" placeholder="E.g. JoeB95">
<br>
<label>Email</label>
<input type="text" name="email" placeholder="E.g. [email protected]">
<br>
<label>Password</label>
<input type="password" name="password_1" placeholder="E.g. 8969-545a-r3">
<br>
<!--Submit button goes below here -->
<div id="register"><input type="submit" name="register" data-inline="true" value="Submit"></div>
</form>
<br>
<p>Already a member?</p> <a href="#pagetwo">Sign In</a>
<br>
<span id="result"></span>
<br>
</div>
<div data-role="footer" id="foot" data-position="fixed" data-theme="b">
<h1>footer</h1>
</div>
</div>
<!-- Page One ends here -->
<!-- -->
<!-- Page Two starts here -->
<div data-role="page" id="pagetwo">
<div data-role="header" data-theme="b">
<h1>Welcome</h1>
</div>
<div data-role="main" class="ui-content">
<br>
<br>
<p>Not a member?</p> <a href="#pageone">Signup</a>
<br>
</div>
<div data-role="footer" id="foot" data-position="fixed" data-theme="b">
<h1>footer</h1>
</div>
</div>
functions.js文件：（Ajax的IFY）
代码Ajax的ifying形式如下。我不确定这里是否存在任何错误。
// AJAX-ify the form
$(document).on("pagecreate","#pageone",function()
{
$("#register").click(function() {
$.post($("#NewForm").attr("action"),
$("#NewForm :input").serializeArray(),
function(info){ $("#result").html(info);
});
});
$("#NewForm").submit(function() {
return false;
});
});
db.php中的文件：
此代码的工作，因为它与数据库连接和我以前用过它。
<?php
//put your connection code here
$servername = 'localhost';
$username = 'admin_example';
$password = '123456-7';
$dbname = 'example_DB';
// create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully, <br>";
?>
include.php文件：
这是我相信的问题。在error_log中，它指向第8行和第11行作为问题区域;
PHP警告：mysqli_query（）预计参数1是mysqli的，在的public_html /登录/ include.php空给定第8行
PHP警告：mysqli_error（）预计参数1是mysqli的，空在第11行的public_html/Login/include.php中给出
我知道有关于这些错误的类似主题，但我不能直接将它与我的关联。任何人都可以提出什么问题，需要改变什么？谢谢。
<?php
$user = $_POST['username'];
$email = $_POST['email'];
$password_1 = $_POST['password_1'];
$access = md5($password_1);
$sql = "INSERT INTO users (`username`, `email`, `password`) VALUES ('$username', '$email', '$password_1')";
if(mysqli_query($conn,$sql)){
echo "Successfully Inserted";
} else {
echo ("Error description: " . mysqli_error($conn));
}
?>
除非您在示例中缺少代码，否则include.php中的$ conn'为null。即使连接在db.php中工作，include.php也不应该能够访问'$ conn'。尝试在查询调用之前在include.php中包含/需要db.php。 – cteski