D3数据地图数据结构（多年，所有国家）

Question

我需要关于如何获得我的数据结构的帮助。我试图使用D3做一个数据图和散点图（使用链接的视图）。该数据集我使用的是这样的：

预期寿命（出生）：

[{"country":"Abkhazia","1995":null,"1996":null,"1997":null,"1998":null,"1999":null,"2000":null,"2001":null,"2002":null,"2003":null,"2004":null,"2005":null,"2006":null,"2007":null,"2008":null,"2009":null,"2010":null,"2011":null,"2012":null,"2013":null,"2014":null,"2015":null,"2016":null}, 
{"country":"Afghanistan","1995":49.4,"1996":49.7,"1997":49.5,"1998":48.6,"1999":50,"2000":50.1,"2001":50.4,"2002":51,"2003":51.4,"2004":51.8,"2005":52,"2006":52.1,"2007":52.4,"2008":52.8,"2009":53.3,"2010":53.6,"2011":54,"2012":54.4,"2013":54.8,"2014":54.9,"2015":53.8,"2016":52.72}, 
{"country":"Akrotiri and Dhekelia","1995":null,"1996":null,"1997":null,"1998":null,"1999":null,"2000":null,"2001":null,"2002":null,"2003":null,"2004":null,"2005":null,"2006":null,"2007":null,"2008":null,"2009":null,"2010":null,"2011":null,"2012":null,"2013":null,"2014":null,"2015":null,"2016":null}, 
etc. 

国家代码：

var countryCodes =[ 
["af", "AFG", "Afghanistan"], 
["ax", "ALA", "Åland Islands"], 
["al", "ALB", "Albania"], 
["dz", "DZA", "Algeria"], 
etc. 

GDP的百分比去医疗：

[{"country":"Abkhazia","1995":null,"1996":null,"1997":null,"1998":null,"1999":null,"2000":null,"2001":null,"2002":null,"2003":null,"2004":null,"2005":null,"2006":null,"2007":null,"2008":null,"2009":null,"2010":null}, 
{"country":"Afghanistan","1995":null,"1996":null,"1997":null,"1998":null,"1999":null,"2000":null,"2001":null,"2002":5.7,"2003":6.8,"2004":6.4,"2005":6.6,"2006":6.8,"2007":7.3,"2008":7.0,"2009":7.6,"2010":7.6}, 
{"country":"Akrotiri and Dhekelia","1995":null,"1996":null,"1997":null,"1998":null,"1999":null,"2000":null,"2001":null,"2002":null,"2003":null,"2004":null,"2005":null,"2006":null,"2007":null,"2008":null,"2009":null,"2010":null}, 
{"country":"Albania","1995":2.6,"1996":4.0,"1997":4.8,"1998":5.3,"1999":5.8,"2000":6.4,"2001":6.0,"2002":6.3,"2003":6.2,"2004":6.9,"2005":6.8,"2006":6.7,"2007":6.9,"2008":6.7,"2009":6.9,"2010":6.5}, 
etc. 

我想什么（1/2） 按照我的老师的意见，我终于写了下面的代码：

// If error, show in console 
if (error) return console.warn(error); 

// Default year and country when first rendering map 
var year = 2011; 
var country = "Netherlands"; 

data = {} 

// Using colorblind safe colors from colorbrewer2.org 
var colorArray = ["lowest", "low", "middle", "high", "highest"] 

    // number of years (= number of objects per country minus 1 for the name of the country) 
    number = Object.keys(lifeExpectancy[1]).length - 1 


    // getting the minimum and the maximum life expectancy of the entire dataset 
    var min = Number.MAX_VALUE, 
    max = -Number.MAX_VALUE; 

    lifeExpectancy.forEach(function (o) { 
     Object.keys(o).forEach(function (k) {     
      if (k !== 'country' && o[k] !== null) { 
       min = Math.min(min, o[k]); 
       max = Math.max(max, o[k]); 
      } 
     }); 
    }); 

    // calculating the denumerator 
    var denumerator = max /5; 


    // // Make the datastructure 
    for (var i = 0; i < lifeExpectancy.length; i++){ 


     for (var j = 0; j < countryCodes.length; j++){ 


       if(lifeExpectancy[i]["country"] == countryCodes[j][2]){ 

        data[countryCodes[j][1]] = {} 

        for(var k = 0; k < number; k++){ 
         var year = 1995 + k; 
         data[countryCodes[j][1]][Object.keys(lifeExpectancy[i])[k]] = 
          {fillKey: (Math.floor((lifeExpectancy[i][year] - min)/denumerator)), 
          country: lifeExpectancy[i]["country"], 
          lifeExpectancy: lifeExpectancy[i][Object.keys(lifeExpectancy[i])[k]], 
          healthPercGDP: healthPercGDP[i][Object.keys(healthPercGDP[i])[k]]} 
        } 
       } 


     } 
    } 

使用这种数据结构是这样的：

data = {ABW {1995 { country: "Aruba", fillKey:2, healthPercGDP:null, lifeExpectancy:73,62}, 
1996{.........}, 
1997{..........},.........} 
,AFG{1995{ country:"Afghanistan", fillkey: 1, healthPercGDP: null, lifeExpectancy:49,62} etc.}} 

然而，我发现D3.datamaps的工作，

我需要以下结构：

data = {1995{ABW{.....},AFG{.....},....} 
1996{ABW{....},AFG{....},....}etc.} 

我试过（2/2）

var data2 = {}; 
     // Make the datastructure 
    for (var i = 0; i < lifeExpectancy.length; i++){ 

     for(var k = 0; k < number; k++){ 
      var year = 1995 + k; 
      data2[Object.keys(lifeExpectancy[i])[k]] = {} 


      for (var j = 0; j < countryCodes.length; j++){ 


       if(lifeExpectancy[i]["country"] == countryCodes[j][2]){ 

        data2[Object.keys(lifeExpectancy[i])[k]][countryCodes[j][1]] = { 
         fillKey: (Math.floor((lifeExpectancy[i][year] - min)/denumerator)), 
         country: lifeExpectancy[i]["country"], 
         lifeExpectancy: lifeExpectancy[i][Object.keys(lifeExpectancy[i])[k]], 
         healthPercGDP: healthPercGDP[i][Object.keys(healthPercGDP[i])[k]]} 
       } 
      } 
     } 
    } 

然而代码的最后块只是给我：

data2={1995{SSD{country: "South Sudan", fillKey:1, healthPercGDP:null, lifeExpectancy: 52.7}},1996{SSD{.....}},1997{SSD{....}}, etc.} 

我只得到字典，1995年至2016年，所有南苏丹的价值。更令人感到奇怪的是，南苏丹不是国家代码清单中的最后一个变量。

完整的数据集：

https://github.com/JappaB/DataProcessing/tree/master/Homework/week-6

Answer 1

这里有一个简单的方法来做到这一点：

var lifeExpectancyData = [{"country":"Abkhazia","1995":null,"1996":null,"1997":null,"1998":null,"1999":null,"2000":null,"2001":null,"2002":null,"2003":null,"2004":null,"2005":null,"2006":null,"2007":null,"2008":null,"2009":null,"2010":null,"2011":null,"2012":null,"2013":null,"2014":null,"2015":null,"2016":null}, 
 
    {"country":"Afghanistan","1995":49.4,"1996":49.7,"1997":49.5,"1998":48.6,"1999":50,"2000":50.1,"2001":50.4,"2002":51,"2003":51.4,"2004":51.8,"2005":52,"2006":52.1,"2007":52.4,"2008":52.8,"2009":53.3,"2010":53.6,"2011":54,"2012":54.4,"2013":54.8,"2014":54.9,"2015":53.8,"2016":52.72}, 
 
    {"country":"Akrotiri and Dhekelia","1995":null,"1996":null,"1997":null,"1998":null,"1999":null,"2000":null,"2001":null,"2002":null,"2003":null,"2004":null,"2005":null,"2006":null,"2007":null,"2008":null,"2009":null,"2010":null,"2011":null,"2012":null,"2013":null,"2014":null,"2015":null,"2016":null}] 
 

 
    var healthcareData = [{"country":"Abkhazia","1995":null,"1996":null,"1997":null,"1998":null,"1999":null,"2000":null,"2001":null,"2002":null,"2003":null,"2004":null,"2005":null,"2006":null,"2007":null,"2008":null,"2009":null,"2010":null}, 
 
    {"country":"Afghanistan","1995":null,"1996":null,"1997":null,"1998":null,"1999":null,"2000":null,"2001":null,"2002":5.7,"2003":6.8,"2004":6.4,"2005":6.6,"2006":6.8,"2007":7.3,"2008":7.0,"2009":7.6,"2010":7.6}, 
 
    {"country":"Akrotiri and Dhekelia","1995":null,"1996":null,"1997":null,"1998":null,"1999":null,"2000":null,"2001":null,"2002":null,"2003":null,"2004":null,"2005":null,"2006":null,"2007":null,"2008":null,"2009":null,"2010":null}] 
 

 
    var countryCodes = [ 
 
    \t ["ab", "AB", "Abkhazia"], 
 
    \t ["af", "AFG", "Afghanistan"], 
 
    ]; 
 

 
    function isNumber(object) { 
 
    \t return !isNaN(object); 
 
    } 
 

 
    var years = Object.keys(lifeExpectancyData[0]) 
 
    \t .filter(isNumber) 
 

 
    var data = {} 
 

 
    years.forEach(function(year) { 
 

 
    \t data[year] = {}; 
 

 
    \t countryCodes.forEach(function(row) { 
 
    \t \t let code = row[1]; 
 
    \t \t let country = row[2]; 
 

 
    \t \t function matchesCountry(obj) { 
 
    \t \t \t return obj.country === country; 
 
    \t \t } 
 

 
    \t \t let fillKey = 0; \t // calculate fillkey 
 

 
    \t \t let lifeExpectancyFiltered = lifeExpectancyData.filter(matchesCountry); 
 

 
    \t \t let healthcarePercentageFiltered = healthcareData.filter(matchesCountry); 
 

 
    \t \t let lifeExpectancy = lifeExpectancyFiltered.length ? lifeExpectancyFiltered[0][year] || 0 : 0; 
 
    \t \t let healthcarePercentage = healthcarePercentageFiltered.length ? healthcarePercentageFiltered[0][year] || 0 : 0; 
 
    
 
    \t \t data[year][code] = { 
 
    \t \t \t fillKey: fillKey, 
 
    \t \t \t country: country, 
 
    \t \t \t lifeExpectancy: lifeExpectancy, 
 
    \t \t \t healthcarePercentage: healthcarePercentage 
 
    \t \t } 
 
    \t }) 
 
    }) 
 

 
    console.log(data)