2016-07-04 116 views
0

我有以下架构。它的用户和文档有几个字段。我需要的是,一旦用户注册密码变得隐藏,无论哪个数据库查询(例如查找,更新等),我运行密码始终保持隐藏状态。隐藏所有MongoDB查询的密码

我知道在mongo查询中排除/制作密码:0截至目前我排除密码使用以下方法:

User.find({} , {password: 0}).populate('favoriteListings').populate('myListings').populate('profilePicture').limit(size).skip(itemsToSkip) 
     .exec(function (err, result) { // LIMIT THE RESULT TO 5 DOCUMENTS PER QUERY 
     if (err) return next(err) 
     return res.json(result) 
     }) 

即我排除密码从json结果单独在所有查询。我需要的是做一些类似密码:{hidden:true}并且每当我做任何查询密码不返回。

var mongoose = require('mongoose'); 
var Schema = mongoose.Schema; // creating schema 
var Listing = require('../listing/listingModel'); 
var Media = require('../media/mediaModel'); 

var UserSchema = new Schema({ 
    email: {type: String,default: null}, // EMAIL ID AND PASSWORD ARE TO BE KEPT ON MAIN OF SCHEMA 
    password: {type: String,default: null}, 

    personal: { // personal information 
    firstName: {type: String,default: null}, 
    lastName: {type: String,default: null}, 
    dateOfBirth: { type: Date, default: Date.now }, 
    description: {type: String,default: null}, 
    contactNo: {type: String,default: '0000-0000-0000'}, 
    gender: { 
     male: {type: Boolean,default: true}, 
     female: {type: Boolean,default: false} 
    } 

    }, 

    preferences: { 
    budget: {type: Number,default: 0}, 
    moveInDate: { type: Date, default: Date.now }, 
    profileViewable: {type: Boolean,default: true} 
    }, 

    background: { // Has an array of work experiences 
    workExperience: [{ // can have multiple experiences so it is an array 
     employer: {type: String,default: null}, 
     position: {type: String,default: null}, 
     descrpiton: {type: String,default: null}, 
     startDate: {type: Date,default: Date.now}, 
     endDate: {type: Date,default: Date.now} 
    }] 
    }, 

    profilePicture: { type: Schema.Types.ObjectId, ref: 'Media' }, 
    favoriteListings: [{ type: Schema.Types.ObjectId, ref: 'Listing' }], 
    myListings: [{ type: Schema.Types.ObjectId, ref: 'Listing' }], 
    status: {type: Boolean,default: true} // STATUS OF ENTRY, BY DEFAULT ACTIVE=TRUE 
}, 
    { 
    // MAKING VIRTUALS TRUE 
    toObject: { 
     virtuals: true 
    }, 
    toJSON: { 
     virtuals: true 
    }, 

    timestamps: true, // FOR createdAt and updatedAt 
    versionKey: false, 
    id: false // because toObject virtuals true creates another id field in addition to _id so making it false 
    } 

) 

UserSchema 
    .virtual('fullName') 
    .get(function() { 
    // console.log(this.createdAt) 
    if (this.firstName != null && this.lastName != null) {return this.name.firstName + ' ' + this.name.lastName} 
    else 
     return null 
    }) 

var User = mongoose.model('User', UserSchema) 

module.exports = User 

以下为登录用户

User.findOne({ 
    email: req.body.email 
}).select('+hash +salt').exec(function (err, validadmin) { 
    if (err) return next(err) 

    if (!validadmin) { 
    res.json({ success: false, message: 'Authentication failed. User not found.' }) 
    } else if (validadmin) { 
    var decryptedPassword = CryptoJS.AES.decrypt(validadmin.password, myPasswordKey) // DECRYPTING PASSWORD 
    // OBTAINED FROM DB TO MATCH WITH PASSWORD GIVEN BY USER 
    decryptedPassword = decryptedPassword.toString(CryptoJS.enc.Utf8) 
    console.log(decryptedPassword) 
    console.log(req.body.password) 
    // check if password matches 
    if (decryptedPassword != req.body.password) { 
     return res.json({ success: false, message: 'Authentication failed. Wrong password.' }) 
    } else { 
     // CREATES TOKEN UPON SUCCESSFUL LOGIN 
     var token = jwt.sign(validadmin, app.get('superSecret'), { 
     expiresIn: 24 * 60 * 60 
     }) 

     // LOGIN SUCCESSFUL 
     return res.json({ 
     success: true, 
     message: 'LOGIN SUCCESSFUL!', 
     token: token 
     }) 
    } 
    } 
}); 

回答

1

添加代码:

select: false 

到您的用户模型中的密码属性。

password: {type: String,default: null,select:false} 

btw您应该在将密码保存到数据库之前加密密码!

+0

在这种情况下,密码从查询结果中隐藏起来。但是当我使用密码和电子邮件进行登录时,出现以下错误:TypeError:无法读取未定义的属性“salt”。顺便说一句我使用jwt的密码加密 – SyedAliRazaSherazi

+0

在你的登录策略,你必须检索数据库的用户,并检查它对试图登录正确的用户?在查找用户的查询中,在find方法之后添加.select('+ hash + salt')。 –

+0

如果您不想在查询数据库以显示用户配置文件时获取散列和salt,还可以执行以下操作:User.find(id).. select(' - hash - 盐') 我认为这将工作 –