来自url的Python http请求，以xml格式回答

Question

我将使用python http请求。我需要从httpbin.org/get获得请求，然后获取其内容，将其转换为xml格式，并将其发回给httpbin.org/post。我还需要每分钟处理10-15个请求。我需要使用grequests（异步）还是请求库？我试过的代码：

import grequests 

urls = ['http://www.google.com/finance','http://finance.yahoo.com/','http://www.bloomberg.com/'] 
def def1(response,**kwargs): 
print(response.url," is available...") 
def def2(response,**kwargs): 
print(response.url," content is: ",response.content) 
def requestAsync(urls): 
responses=[] 
for u in urls: 
    get=grequests.get(u,hooks={'response':def1}) 
    post=grequests.post("http://httpbin.org/post",hooks={'response':def2},data="some data") 
    responses.append(get) 
    responses.append(post) 
return grequests.map(responses) 
print(requestAsync(urls)) 

Answer 1

grequests绝对是实现设计的一种更好的方式，但实现起来会比较困难。

您面对的代码是什么问题？