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我有多个CSV文件象下面这样:awk格式化csv文件| unix | Solaris | AWK
~/Prod/Jcs/BIN/Dash_PPLP/load$ ls -lt *csv
-rw-rw-r-- 1 tellus tellus 81 Sep 7 14:27 extraction_MBBSCS_PPL_USAGE_IMPORT.csv
-rw-rw-r-- 1 tellus tellus 83 Sep 7 14:27 extraction_MBBSCS_PPL_INVOICE_IMPORT.csv
-rw-rw-r-- 1 tellus tellus 71 Sep 7 14:27 extraction_INVOICE.csv
-rw-rw-r-- 1 tellus tellus 69 Sep 7 14:27 extraction_USGRERUN.csv
-rw-rw-r-- 1 tellus tellus 69 Sep 7 14:27 extraction_USG.csv
-rw-rw-r-- 1 tellus tellus 72 Sep 7 14:27 extraction_LIA.csv
-rw-rw-r-- 1 tellus tellus 74 Sep 7 14:27 extraction_MSISDN.csv
通过打开一个文件
cat extraction_LIA.csv
PPL_LIABILITY,2468705,Fri Sep 01 06:56:41 2017,Fri Sep 01 06:58:33 2017
格式名,行,START_TIME和END_TIME每个流我要监控,以使它们“可加载”到ORACLE表中。
我已经做出了这样的脚本做变换和覆盖它们每一个,象下面这样:
cat transform_to_load.bash
#!/bin/bash
csv_files=$(ls *.csv)
for i in $csv_files
do
x=$(nawk 'BEGIN { OFS=","; FS=","} {split($3,a," ");split($3,b," ")}
{$3=a[3]"/"a[2]"/"a[5]" "a[4];$4=b[3]"/"b[2]"/"b[5]" "b[4]}
{print}' $i)
echo $x > $i
done
的问题是我NAWK:
x=$(nawk 'BEGIN { OFS=","; FS=","} {split($3,a," ");split($3,b," ")}
{$3=a[3]"/"a[2]"/"a[5]" "a[4];$4=b[3]"/"b[2]"/"b[5]" "b[4]}
{print}' $i)
产生以下(开始时间与结束时间相同)
[email protected]:~/Prod/Jcs/BIN/Dash_PPLP/load$ cat extraction_LIA.csv
PPL_LIABILITY,2468705,01/Sep/2017 06:56:41,01/Sep/2017 06:56:41
我想实现的是将其格式化为w ithnak(SunOS)像这样每个人:
PPL_LIABILITY,2468705,01/Sep/2017 06:56:41,01/Sep/2017 06:58:33
你能帮我用我的nawk输出正确的格式吗?
非常感谢!
嘿!非常感谢,所以调整到4美元将解决它,正确?? –
@tln_jupiter:是的,你可以看到'$ 3'意思是第3个字段/列 –
真的很有用,非常感谢:) –