我有一个问题,有一个页面上有多个对话框,并将它们链接到由PHP生成的ID。我想多图像是指向包含内容的对话......这里是我的代码:jQuery UI多对话框和PHP
PHP:
<div id="children">
<?php
$children = array_values(get_pages(array('child_of' => $post->ID)));
foreach($children as $ch => $child){
echo '<div id="dialog-'.$child->ID.'" title="Basic dialog">';
echo $child->post_content;
echo '</div>';
}
foreach($children as $ch => $child){
$attachments = get_posts(array('numberposts'=> 1, 'post_parent' => $child->ID, 'post_type' => 'attachment', 'order' => 'DESC', 'orderby' => 'post_date'));
//print_r($attachments);
foreach($attachments as $a => $attachment){
echo '<a href="#opener-'.$child->ID.'" id="opener-'.$child->ID.'" >';
echo '<img class="attachment-thumb" src="'.$attachment->guid.'" width="150" height="150" />';
echo '</a> ';
}
}
//print_r($children)
?>
现在我认识到我的jQuery是生产每个ID与而不是实际的PHP ID,但我不知道如何设置它,所以jQuery将链接到适当的对话框和开场白。我需要使用Ajax吗?
的jQuery:
<script>
$(function() {
var options = {
autoOpen: false,
width: 'auto',
modal: true
};
var num = 1;
$("#children").each(function() {
var dlg = $('#dialog-' + num).dialog(options);
$('#opener-' + num).click(function() {
dlg.dialog("open");
return false;
});
num = num + 1;
});
});
</script>
</div>