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所以基本上我试图嘲笑我的依赖关系在控制器上,我想使用Mockery的ordered()
功能。嘲讽命令嘲笑
$request = \Mockery::mock('Silhouette\Http\Request');
$response = \Mockery::mock('Silhouette\Http\Response');
$response->shouldReceive("setContent")->ordered();
$db = \Mockery::mock('Dabble\Database');
$configData = \Mockery::mock('Silhouette\Configuration\ConfigurationData');
$configData->shouldReceive("get")->andReturn(array(18, 23))->ordered();
上述测试是成功的,即使所述$configData->get()
被在控制器$response->setContent()
之前调用。 此外,如果我扭转嘲笑的顺序,我仍然geta成功的测试。
$request = \Mockery::mock('Silhouette\Http\Request');
$db = \Mockery::mock('Dabble\Database');
$configData = \Mockery::mock('Silhouette\Configuration\ConfigurationData');
$configData->shouldReceive("get")->andReturn(array(18, 23))->ordered();
$response = \Mockery::mock('Silhouette\Http\Response');
$response->shouldReceive("setContent")->ordered();
任何想法我在做什么错在这里?谢谢
声明,这种方法有望在相对于类似的标记方法以特定的顺序被调用。 所以它们表示同一个模拟对象的方法。谢谢! – 2014-09-03 14:16:36