2017-04-03 64 views
-1

我试图过滤这个数组来获取id并将字符串转换为数字。我想使用过滤器和地图?想知道如何尽可能清楚。如何在数组上使用array.filter + map

var pets = [ 
    { id: '1', name: 'rupert', readyForHome: 'No', age: 12, personality: ['friendly', 'lazy', 'loving']}, 
    { id: '2', name: 'mrs fluffy', readyForHome: 'Yes', age: 2, personality: ['affectionate', 'playful', 'shy']}, 
    { id: '3', name: 'tabitha', readyForHome: 'Yes', age: 4, personality: ['aggressive', 'independent']}, 
    { id: '4', name: 'lily', readyForHome: 'No', age: 8, personality: ['friendly', 'playful', 'mischievous']}, 
]; 
+0

请添加搜索参数,输出和你试过了什么。您也可以在这里看看:[mcve] –

回答

0

所有你需要的是map静下心来,一个ID数组作为数字:

pets = pets.map(function(pet) { 
    return Number(pet.id); 
}); 

var pets=[{id:"1",name:"rupert",readyForHome:"No",age:12,personality:["friendly","lazy","loving"]},{id:"2",name:"mrs fluffy",readyForHome:"Yes",age:2,personality:["affectionate","playful","shy"]},{id:"3",name:"tabitha",readyForHome:"Yes",age:4,personality:["aggressive","independent"]},{id:"4",name:"lily",readyForHome:"No",age:8,personality:["friendly","playful","mischievous"]}]; 
 

 
pets = pets.map(function(pet) { 
 
    return Number(pet.id); 
 
}); 
 

 
console.log(pets);

+0

感谢您的帮助,但是我的11次返回“对象”。这里是我的代码 –

+0

函数petSorter(pet){cat_l = cats.map(function(pet){ return Number(pet.id); }); } console.log(cats); –

+0

@JacobJabocJones,查看更完整的代码示例可能会有所帮助,如果这有助于您可以使用[JSFiddle](https://jsfiddle.net/)。 – KevBot

0
var petIds = pets.map(function (pet) { 
    petId = parseInt(pet.id); 
    return petId; 
}); 
+0

考虑提供解​​释给你的代码 – arghtype

相关问题