SQL，如何从两个不同的查询中总结两个总和

Question

我想在两种不同的条件下获取同一个变量的总和。只是想知道是否有办法将这些加在一起。查询的细节并不太相关。基本上只是试图拿第一笔款项，并添加第二笔款项。

例如 -

首先查询：

select sum(amt_tot) 
    from agbgift, aprdclb 
    where agbgift_id = '1' and agbgift_id = aprdclb_id 

第二个查询：

select sum(amt_tot) 
    from agbgift, aprxref, aprdclb where 
    aprxref_id = '1' and 
    agbgift_id = aprxref_xref_id and 
    aprxref_id = aprdclb_id and 
    xref_code in ('SPS','BUS','ORG','OWN','FDN'); 

最终的结果我找的是 '第一个查询点心' +“第二个查询总和'

Answer 1

使用子句可以轻松实现，如果使用不起作用，可以在from子句中使用别名

with b ( select sum(amt_tot) as bsum 
    from agbgift, aprxref, aprdclb where 
    aprxref_id = '1' and 
    agbgift_id = aprxref_xref_id and 
    aprxref_id = aprdclb_id and 
    xref_code in ('SPS','BUS','ORG','OWN','FDN')) 
, a (select sum(amt_tot) asum 
    from agbgift, aprdclb 
    where agbgift_id = '1' and agbgift_id = aprdclb_id ) 
select a.asum + b.bsum 
from a, b 

这是真的在这种情况下：

select a.asum + b.bsum 
from (select sum(amt_tot) asum 
    from agbgift, aprdclb 
    where agbgift_id = '1' and agbgift_id = aprdclb_id) as a, 
    ( select sum(amt_tot) as bsum 
    from agbgift, aprxref, aprdclb where 
    aprxref_id = '1' and 
    agbgift_id = aprxref_xref_id and 
    aprxref_id = aprdclb_id and 
    xref_code in ('SPS','BUS','ORG','OWN','FDN')) as b 

Answer 2

在这种情况下，它是这样简单：

SELECT 
/* Query 1 (in parentheses) */ 
(select sum(amt_tot) 
    from agbgift, aprdclb 
    where agbgift_id = '1' and agbgift_id = aprdclb_id) 

    + /* plus */ 

/* Query 2 (also in parentheses) */ 
    (select sum(amt_tot) 
    from agbgift, aprxref, aprdclb where 
    aprxref_id = '1' and 
    agbgift_id = aprxref_xref_id and 
    aprxref_id = aprdclb_id and 
    xref_code in ('SPS','BUS','ORG','OWN','FDN'))