ActiveRecord日期时间比较

我有日期时间

的out_date和in_date情况下，我有这个疑问：

reservations = Reservation.where("bookable_id = :bookable_id AND bookable_type = :bookable_type AND status <> :status AND ((:out_date >= check_out_date AND :out_date <= check_in_date) OR (:in_date <= check_in_date AND :in_date >= check_out_date) OR (:out_date <= check_in_date AND :in_date >= check_in_date))", :bookable_id => params[:bookable_id], :bookable_type => params[:bookable_type], :status => Reservation::STATUS_CHECKED_IN, :out_date => out_date, :in_date => in_date)

我总是空集，即使我应该得到回报的元组。

我尝试了这些一些变体：

out_date.utc 

out_date.utc.to_s(:db)

一切似乎是工作。如何构建这个查询？

控制器代码：

in_date = DateTime.strptime params[:checkin], "%Y-%m-%d %H:%M" 
    out_date = DateTime.strptime params[:checkout], "%Y-%m-%d %H:%M" 

    #check collision with non-recurring reservations 
    reservations = Reservation.where("bookable_id = :bookable_id AND bookable_type = :bookable_type AND status <> :status AND ((:out_date >= check_out_date AND :out_date <= check_in_date) OR (:in_date <= check_in_date AND :in_date >= check_out_date) OR (:out_date <= check_in_date AND :in_date >= check_in_date))", :bookable_id => params[:bookable_id], :bookable_type => params[:bookable_type], :status => Reservation::STATUS_CHECKED_IN, :out_date => out_date, :in_date => in_date) 
    logger.info(reservations) 
    if !reservations.empty? 
    @error_message = "This Asset has already been reserved for those dates" 
    return 
    end

同样在导轨控制台，简单的查询失败：

1.9.3p0 :007 > Reservation.find_by_id 31 
    Reservation Load (0.7ms) SELECT `reservations`.* FROM `reservations` WHERE `reservations`.`id` = 31 LIMIT 1 
=> #<Reservation id: 31, bookable_id: 11, bookable_type: "Asset", user_id: 1, check_out_date: "2012-07-07 08:00:00", check_in_date: "2012-07-07 10:00:00", notes: "rec", status: "Ready", is_recurring: true, repeat_count: 5> 


1.9.3p0 :009 > Reservation.where " ? >= check_out_date AND ? <= check_in_date",DateTime.new(2012,7,7,9),DateTime.new(2012,7,7,9) 
    Reservation Load (0.5ms) SELECT `reservations`.* FROM `reservations` WHERE ('2012-07-07 09:00:00' >= check_out_date AND '2012-07-07 09:00:00' <= check_in_date) 
=> []

来源

2012-07-04 Nitish Upreti

“out_date”变量分配在哪里？ –

另外，你应该使用[命名范围]（http://ar.rubyonrails.org/classes/ActiveRecord/NamedScope/ClassMethods.html）。 –

@SimoneCarletti在同一个控制器中。 –

这个错误是因为数据库时间以UTC存储，本地时间不同而且不满足查询条件。

来源

2012-07-04 19:42:00

我读了更新后的代码，显然，这是正确的。确保out_date和in_date是DateTime对象而不是空对象。

你不需要格式化查询，它应该为你处理。

如果要调试SQL查询，您可以使用.to_sql

reservations = Reservation.where("...") # your query 
puts reservation.to_sql 
# => "SELECT ..."

打印查询，并检查值的格式正确无误。

来源

2012-07-04 09:04:58

我得到这个：SELECT COUNT（*）FROM'reservations' WHERE（bookable_id ='11'AND bookable_type ='Asset'AND status <>'Checked In'AND（（''2012-07 -07 09:00:00'> = check_out_date AND'2012-07-07 09:00:00'<= check_in_date）或（'2012-07-07 11:00:00'<= check_in_date AND'2012-07 -07 11:00:00'> = check_out_date）或（'2012-07-07 09:00:00'<= check_in_date AND'2012-07-07 11:00:00'> = check_in_date））） –

This似乎很好。如果check_in_date和check_out_date由rails处理。为什么我没有得到任何结果？ –

在这一点上，问题是查询本身。尝试从更简单的查询开始，然后添加一个条件并查看失败的位置。 –

ActiveRecord日期时间比较

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