如何合并与同类键一个键的值不同的数组的数组元素只

Question

我与PHP的工作，并有一个数组的数组，看起来是这样的：

Array(
    [0] => Array(
      [id] =>1, 
      [name]=>"edward", 
      [asset]=>"somesong.mp3" 
      ), 
    [1] => Array(
      [id] =>1, 
      [name]=>"edward", 
      [asset]=>"somemovie.mov" 
      ), 
    [2] => Array(
      [id] =>2, 
      [name]=>"sally", 
      [asset]=>"anothersong.mp3" 
      ), 
    [3] => Array(
      [id] =>2, 
      [name]=>"sally", 
      [asset]=>"anothermovie.mov" 
      ), 
... 
) 

正如你可以看到，他们的主阵列中每个元素之间的相似性，仅与[asset]键的值不同。我想合并主阵列中的元件以便每个[资产]的两个值被保持在新的元件，这样

FinalArray(
    [0] => Array(
      [id] =>1, 
      [name]=>"edward", 
      [song]=>"somesong.mp3", 
      [movie]=>"somemovie.mov" 
      ), 
    [1] => Array(
      [id] =>2, 
      [name]=>"sally", 
      [song]=>"anothersong.mp3", 
      [movie]=>"anothermovie.mov" 
      ) 
... 
) 

我开始使用内和外foreach()环的组合使用，探索结构

// $person and $person02 are copies of the same array 
foreach($person as $key=>$value){ 
    // grab an element in this loop 
    $currElement=$person[$key]; 
    foreach($person2 as $key2=>$value2){ 
     $currElement2=$person2[$key2]; 
     // compare $currElement to $currElement2 
     if($currElement['id']==$currElement2['id']){ 
      // determine if [asset] is an mp3 or mov 
      $currAsset2=$currElement2['asset']; 
      $currAsset =$currElement['asset']; 

      $ext = substr(strrchr($currAsset,'.'),1) 
      if($ext=='mp3'){ 
       // then we have a song and should store it 
       $song=$currAsset['asset']; 
       $movie=$currAsset2['asset']; 
      }else{ 
       // switch sides if you like 
       $song=$currAsset2['asset']; 
       $movie=$currAsset['asset']; 
      } 
     } 

     // create a new array and add it to the result array 
     $newArrEl = array(
      'id' =>$currElement['id'], 
      'name' =>$currElement['id'], 
      'song' => $song, 
      'movie' => $movie 
     ); 
     $resultArray.push(); // add to final array 
    } 
} 
} 

事情是，我探索了一堆PHP数组函数的组合，似乎无法得到它很正确。所以我希望这里的某个人也能帮助我解决这个问题。我怎样才能获得原始数据与类似的值合并成新的元素添加到最终数组？

Answer 1

看起来你的主号标识是id，我会做与id作为密钥的目标磁盘阵列，通过原始数组迭代只是一次，像这样：

<?php 

$original_array = array(
    array(
     'id' => 1, 
     'name' => 'edwards', 
     'asset' => "somesong.mp3" 
    ), 
    array(
     'id' => 1, 
     'name' => 'edwards', 
     'asset' => "somemovie.mov" 
    ), 
    array(
     'id' => 2, 
     'name' => 'sally', 
     'asset' => "anothersong.mp3" 
    ), 
    array(
     'id' => 2, 
     'name' => 'sally', 
     'asset' => "anothermovie.mov" 
    ) 
); 

$result = array(); 

$fields_map = array(
    '/\.mp3$/iS' => 'song', 
    '/\.mov$/iS' => 'movie' 
); 

foreach($original_array as $item) 
{ 
    $id = $item['id']; 

    if (!isset($result[$id])) 
    { 
     // initial population 
     $result[$id] = array(
      'id' => $id, 
      'name' => $item['name'] 
     ); 
    } 

    if (isset($item['asset'])) 
    { 
     foreach($fields_map as $re => $field_name) 
     { 
      if (preg_match($re, $item['asset'])) 
      { 
       $result[$id][$field_name] = $item['asset']; 
       break; 
      } 
     } 
    } 
} 

var_dump($result); 

注：我使用的是正则表达式因为我假设你可能有更多的扩展需要支持相同的字段（例如mp3，ogg，wav，flac所有映射到字段'歌曲'），而不是简单的hashmap。正则表达式可以很容易地添加更多的字段。

Answer 2

试试这个：

$array = array(
    array(
     'id' => 1, 
     'name' => 'edwards', 
     'asset' => "somesong.mp3" 
    ), 
    array(
     'id' => 1, 
     'name' => 'edwards', 
     'asset' => "somemovie.mov" 
    ), 
    array(
     'id' => 2, 
     'name' => 'sally', 
     'asset' => "anothersong.mp3" 
    ), 
    array(
     'id' => 2, 
     'name' => 'sally', 
     'asset' => "anothermovie.mov" 
    ) 
); 

$res = array(); 

foreach($array as $val){ 
    $res[$val['id']]['id'] = $val['id']; 
    $res[$val['id']]['name'] = $val['name']; 
    if(preg_match('/mp3$/',$val['asset'])){ 
    $res[$val['id']]['song'] = $val['asset']; 
    } 
    if(preg_match('/mov$/',$val['asset'])){ 
    $res[$val['id']]['movie'] = $val['asset']; 
    } 
} 
$res = array_values($res); 

echo "<pre>"; 
print_r($res);