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这是我的PHP文件。我无法从fyp1中选择截止日期,其中fyp1.code = $tcode
(即我们放入的输入)。请帮忙。从我们输入的其他表格中选择数据
<?php
include('inc/db.php');
if (isset($_POST['submit'])) {
$tcode = $_POST['tcode'];
$idno = $_POST['idno'];
$sname = $_POST['sname'];
$datesub = date("Y-m-d");
$sql = "SELECT * FROM fyp1";
$select = mysql_query($sql,"SELECT deadline from fyp1 where fyp1.code = '$tcode'");
$name = $_FILES['file']['name'];
$tmp_name = $_FILES['file']['tmp_name'];
if ($name && $tcode){
$Location = "S.File/$name";
move_uploaded_file($tmp_name, $Location);
$query = mysql_query("INSERT INTO submission (taskcode,idno,name,file,time,dead) VALUES ('$tcode','$idno','$sname','$name','$datesub','$select')");
header('Location:DisplayNews.php');
}else
die("Please select a file");
}
?>
您应该使用mysqli_ *函数。 PHP的mysql扩展已被弃用,并从PHP 7中删除.http://php.net/manual/en/book.mysqli.php –