2013-12-07 58 views
0

我有这段代码来上传jpg文件。我需要重命名某人上传到newtexture.jpg的文件。如何在php中更改上传文件的名称?

<?php 
$demo_mode = false; 
$upload_dir = 'uploads/'; 
$allowed_ext = array('jpg','jpeg'); 

if(strtolower($_SERVER['REQUEST_METHOD']) != 'post'){ 
    exit_status('Error! Wrong HTTP method!'); 
} 

if(array_key_exists('pic',$_FILES) && $_FILES['pic']['error'] == 0){ 
    $pic = $_FILES['pic']; 
    if(!in_array(get_extension($pic['name']),$allowed_ext)){ 
     exit_status('Only '.implode(',',$allowed_ext).' files are allowed!'); 
    } 
    if($demo_mode){ 
     $line = implode('  ', array(date('r'), $_SERVER['REMOTE_ADDR'], $pic['size'], $pic['name'])); 
     file_put_contents('log.txt', $line.PHP_EOL, FILE_APPEND); 
     exit_status('Uploads are ignored in demo mode.'); 
    } 
    if(move_uploaded_file($pic['tmp_name'], $upload_dir.$pic['name'])){ 
     exit_status('File was uploaded successfuly!'); 
    } 
} 
exit_status('Something went wrong with your upload!'); 

function exit_status($str){ 
    echo json_encode(array('status'=>$str)); 
    exit; 
} 

function get_extension($file_name){ 
    $ext = explode('.', $file_name); 
    $ext = array_pop($ext); 
    return strtolower($ext); 
} 
?> 

PS。它说它大部分是编码的,以便添加更多细节?还有什么...我是学生,我需要它为我的凯普斯通项目,这是一个紧急情况...

回答

4

move_uploaded_file()的第二个参数是新的文件名,所以你需要做的就是改变它到什么你要。

if(move_uploaded_file($pic['tmp_name'], $upload_dir.'newtexture.jpg')){ 
+1

谢谢!我希望我有超过15的声望:) –

+0

@FragkiskosMysirlakis其实,你现在做:) – Popnoodles

+0

是的,哈哈我现在有... –

1

通过你的文件名作为第二个参数中move_uploaded_file()

$fileName = 'newtexture.jpg'; 

if(move_uploaded_file($pic['tmp_name'], $upload_dir.$fileName)){ 
1

move_uploaded_file需要参数:

  1. 临时文件名移动。
  2. 新的永久文件路径。
bool move_uploaded_file (string $filename , string $destination) 

所以,你必须指定第二个参数(路径+新的文件名)。 例如

move_uploaded_file($pic['tmp_name'], $upload_dir.'newtexture.jpg') 
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