如何使用Twitter Streaming API跟踪其他帐户的新追随者我没有登录信息？

Question

我很重视在Ars Technica的这个出色的tutorial上代码，所以我能够跟踪我自己的新追随者，因为我的登录信息是硬编码的。但是，我想追踪其他追随者人们的帐户也是如此。我怎样才能做到这一点没有他们的密码？

import pycurl, json, StringIO 
STREAM_URL = "http://stream.twitter.com/1/statuses/filter.json?follow=[userid1],[userid2]&track=[keyword1],[keyword2]" 
REST_URL = "http://api.twitter.com/1/" 

class Client: 
    def __init__(self): 
     self.friends = [] 
     self.buffer = "" 
     self.userid = None 
     self.conn = pycurl.Curl() 

    def authenticate(self, username, password): 
     output = StringIO.StringIO() 
     self.conn.setopt(pycurl.USERPWD, "%s:%s" % (username, password)) 
     self.conn.setopt(pycurl.URL, REST_URL + "account/verify_credentials.json") 
     self.conn.setopt(pycurl.WRITEFUNCTION, output.write) 
     self.conn.perform() 

    data = json.loads(output.getvalue()) 
    if "error" in data: return False 
    self.userid = data["id"] 
    return True 

    def connect(self): 
     self.conn.setopt(pycurl.URL, STREAM_URL) 
     self.conn.setopt(pycurl.WRITEFUNCTION, self.on_receive) 
     self.conn.perform() 

    def on_receive(self, data): 
     self.buffer += data 
     if data.endswith("\r\n") and self.buffer.strip(): 
      content = json.loads(self.buffer) 
      self.buffer = "" 
      print content 

     if "friends" in content: 
      self.friends = content["friends"] 

     elif "event" in content and content["event"] == "follow": 
      id_list = ['[userid1]','[userid2]'] 
      print "NEW FOLLOWER!!" 
      print "target id:", content["target"]["id"] 
      if content["target"]["id"] in id_list: 
       print content 
       print "New follower:", content["source"]["name"], "(@" + content["source"]["screen_name"] + ")" 
      elif content["source"]["id"] == self.userid: 
       self.friends.append(content["target"]["id"]) 

     elif "text" in content: 
      to = content["in_reply_to_user_id"] 
      if to and to != self.userid and to not in self.friends: return 
      if to == self.userid: print "(REPLY)", 
      print u"{0[user][name]}: {0[text]}".format(content) 

client = Client() 
if client.authenticate("[username]", "[password]"): 
    client.connect() 
else: 
    print "Login credentials aren't valid!" 

Answer 1

的Twitter Taylor Singletary回应the same question在谷歌组Twitter的发展讲座：

这是不幸的是目前尚未 可能与流API。 考虑到追随者/ ID 和朋友/ ID API方法的灵活性，跟踪 随着时间的推移发生变化，这些方法 可能是您最好的途径。